2

我有几个模型，我想将它们分层关联在一起。为简单起见，假设我有这三个：

class Group < ActiveRecord::Base
  acts_as_tree
  has_many :users
end

class User < ActiveRecord::Base
  acts_as_tree
  belongs_to :group
  has_many :posts
end

class Post < ActiveRecord::Base
  acts_as_tree
  belongs_to :user
end

在当前的acts_as_tree 下，每个节点都可以单独地与其他节点分层关联，前提是它们是相同类型的。我想要的是删除对类型标识的这种限制，以便 SomePost.parent 可以将 User 或 Post 作为其父级，并且 SomeUser.parent 可以将另一个用户或组作为其父级。

有什么想法吗？

4

2 回答 2

3

我过去这样做的方法是使用树中的多态容器，映射到特定的单个模型。

class Container < ActiveRecord::Base
   acts_as_tree
   belongs_to :containable, :polymorphic => true 
end

class User
  has_one :container :as => :containable
end
于 2010-01-26T22:28:13.087 回答
0

我设法做到了一点不同，但这可能不适用于您的情况。我正在重构现有代码，并且不想进行任何严重的数据库迁移。

我想要单独的叶子和节点类。两者都继承自树类。

我在 ClassMethods 中添加了两个函数vendor/plugins/acts_as_tree/lib/active_record/acts/tree.rb：

    # Configuration options are:
    #
    # * <tt>foreign_key</tt> - specifies the column name to use for tracking of the tree (default: +parent_id+)
    # * <tt>order</tt> - makes it possible to sort the children according to this SQL snippet.
    # * <tt>counter_cache</tt> - keeps a count in a +children_count+ column if set to +true+ (default: +false+).
    # * <tt>leaf_class_name</tt> - leaf class subtype of base tree class
    # * <tt>node_class_name</tt> - node class subtype of base tree class
    def acts_as_tree_node(options = {})
      configuration = { :foreign_key => "parent_id", :order => nil, :counter_cache => nil, :node_class_name => 'Node', :leaf_class_name => 'Leaf' }
      configuration.update(options) if options.is_a?(Hash)

      belongs_to :parent, :class_name => configuration[:node_class_name], :foreign_key => configuration[:foreign_key], :counter_cache => configuration[:counter_cache]
      #has_many :children, :foreign_key => configuration[:foreign_key], :order => configuration[:order], :dependent => :destroy

      class_eval <<-EOV
        has_many :child_nodes, :class_name => '#{configuration[:node_class_name]}', :foreign_key => "#{configuration[:foreign_key]}", :order => #{configuration[:order].nil? ? "nil" : %Q{"#{configuration[:order]}"}}, :dependent => :destroy
        has_many :child_leaves, :class_name => '#{configuration[:leaf_class_name]}', :foreign_key => "#{configuration[:foreign_key]}", :order => #{configuration[:order].nil? ? "nil" : %Q{"#{configuration[:order]}"}}, :dependent => :destroy

        include ActiveRecord::Acts::Tree::InstanceMethods

        def self.roots
          find(:all, :conditions => "#{configuration[:foreign_key]} IS NULL", :order => #{configuration[:order].nil? ? "nil" : %Q{"#{configuration[:order]}"}})
        end

        def self.root
          find(:first, :conditions => "#{configuration[:foreign_key]} IS NULL", :order => #{configuration[:order].nil? ? "nil" : %Q{"#{configuration[:order]}"}})
        end
      EOV
    end

    # Configuration options are:
    #
    # * <tt>foreign_key</tt> - specifies the column name to use for tracking of the tree (default: +parent_id+)
    # * <tt>order</tt> - makes it possible to sort the children according to this SQL snippet.
    # * <tt>counter_cache</tt> - keeps a count in a +children_count+ column if set to +true+ (default: +false+).
    # * <tt>node_class_name</tt> - the class name of the node (subclass of the tree base)
    def acts_as_tree_leaf(options = {})
      configuration = { :foreign_key => "parent_id", :order => nil, :counter_cache => nil, :node_class_name => 'Node' }
      configuration.update(options) if options.is_a?(Hash)

      belongs_to :parent, :class_name => configuration[:node_class_name], :foreign_key => configuration[:foreign_key], :counter_cache => configuration[:counter_cache]

      class_eval <<-EOV
        include ActiveRecord::Acts::Tree::InstanceMethods

        def self.roots
          find(:all, :conditions => "#{configuration[:foreign_key]} IS NULL", :order => #{configuration[:order].nil? ? "nil" : %Q{"#{configuration[:order]}"}})
        end

        def self.root
          find(:first, :conditions => "#{configuration[:foreign_key]} IS NULL", :order => #{configuration[:order].nil? ? "nil" : %Q{"#{configuration[:order]}"}})
        end
      EOV
    end

然后，在 InstanceMethods 中，我只添加了一个函数：

    # Returns list of children, whether nodes or leaves.
    #
    # NOTE: Will not return both, because that would take two queries and
    # order will not be preserved.
    def children
      child_leaves.count == 0 ? child_nodes : child_leaves
    end

这有点小技巧，但它对我有用，因为每个节点都有所有一种类型的潜艇。您可以使用该children函数来获得不同的行为，如下所示：

def children
  child_nodes | child_leaves
end

但是它仍然需要一个额外的查询，并且你会丢失你的订单和范围和东西。

最后，在我的 Node 类中，我有

acts_as_tree_node :node_class_name => 'NodeMatrix', :leaf_class_name => 'LeafMatrix'

在我的 Leaf 课程中，以下内容：

acts_as_tree_leaf :node_class_name => 'NodeMatrix'

这两个都继承自 TreeMatrix，它是纯虚拟的（实际上没有任何东西被实例化为 TreeMatrix，它只是一个基类）。

同样，这是非常特定于应用程序的。但它让您了解如何修改acts_as_tree。

于 2010-04-02T23:15:17.000 回答