271

我正在用 PHP 构建一个 REST Web 服务客户端,目前我正在使用 curl 向服务发出请求。

如何使用 curl 发出经过身份验证的(http 基本)请求?我必须自己添加标题吗?

4

11 回答 11

449

你要这个:

curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);  

Zend 有一个 REST 客户端和 zend_http_client,我确信 PEAR 有某种包装器。但它很容易自己做。

所以整个请求可能看起来像这样:

$ch = curl_init($host);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/xml', $additionalHeaders));
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_TIMEOUT, 30);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $payloadName);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
$return = curl_exec($ch);
curl_close($ch);
于 2010-01-26T15:45:41.030 回答
149

CURLOPT_USERPWD基本上发送user:password带有 http 标头的字符串的 base64,如下所示:

Authorization: Basic dXNlcjpwYXNzd29yZA==

因此,除了CURLOPT_USERPWD您还可以使用HTTP-Requestheader 选项以及下面的其他标题:

$headers = array(
    'Content-Type:application/json',
    'Authorization: Basic '. base64_encode("user:password") // <---
);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
于 2014-03-12T16:43:18.903 回答
47

直接使用 CURL 的最简单和原生的方式。

这对我有用:

<?php
$login = 'login';
$password = 'password';
$url = 'http://your.url';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($ch, CURLOPT_USERPWD, "$login:$password");
$result = curl_exec($ch);
curl_close($ch);  
echo($result);
于 2015-08-28T13:17:16.690 回答
10

您只需要指定 CURLOPT_HTTPAUTH 和 CURLOPT_USERPWD 选项:

$curlHandler = curl_init();

$userName = 'postman';
$password = 'password';

curl_setopt_array($curlHandler, [
    CURLOPT_URL => 'https://postman-echo.com/basic-auth',
    CURLOPT_RETURNTRANSFER => true,

    CURLOPT_HTTPAUTH => CURLAUTH_BASIC,
    CURLOPT_USERPWD => $userName . ':' . $password,
]);

$response = curl_exec($curlHandler);
curl_close($curlHandler);

或指定标题:

$curlSecondHandler = curl_init();

curl_setopt_array($curlSecondHandler, [
    CURLOPT_URL => 'https://postman-echo.com/basic-auth',
    CURLOPT_RETURNTRANSFER => true,

    CURLOPT_HTTPHEADER => [
        'Authorization: Basic ' . base64_encode($userName . ':' . $password)
    ],
]);

$response = curl_exec($curlSecondHandler);
curl_close($curlSecondHandler);

贪吃例子:

use GuzzleHttp\Client;
use GuzzleHttp\RequestOptions;

$userName = 'postman';
$password = 'password';

$httpClient = new Client();

$response = $httpClient->get(
    'https://postman-echo.com/basic-auth',
    [
        RequestOptions::AUTH => [$userName, $password]
    ]
);

print_r($response->getBody()->getContents());

https://github.com/andriichuk/php-curl-cookbook#basic-auth

于 2019-06-07T22:38:56.183 回答
7

与 SOAP 不同,REST 不是标准化协议,因此拥有“REST 客户端”有点困难。但是,由于大多数 RESTful 服务使用 HTTP 作为其底层协议,因此您应该能够使用任何 HTTP 库。除了 cURL,PHP 还通过 PEAR 提供了这些:

HTTP_Request2

取代

HTTP_Request

他们如何进行 HTTP 基本身份验证的示例

// This will set credentials for basic auth
$request = new HTTP_Request2('http://user:password@www.example.com/secret/');

还支持 Digest Auth

// This will set credentials for Digest auth
$request->setAuth('user', 'password', HTTP_Request2::AUTH_DIGEST);
于 2010-01-27T03:24:11.830 回答
7

如果授权类型是 Basic auth 并且发布的数据是 json 那么这样做

<?php

$data = array("username" => "test"); // data u want to post                                                                   
$data_string = json_encode($data);                                                                                   
 $api_key = "your_api_key";   
 $password = "xxxxxx";                                                                                                                 
$ch = curl_init(); 
curl_setopt($ch, CURLOPT_URL, "https://xxxxxxxxxxxxxxxxxxxxxxx");    
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 20);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");  
curl_setopt($ch, CURLOPT_POST, true);                                                                   
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);                                                                  
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);     
curl_setopt($ch, CURLOPT_USERPWD, $api_key.':'.$password);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); 
curl_setopt($ch, CURLOPT_HTTPHEADER, array(   
    'Accept: application/json',
    'Content-Type: application/json')                                                           
);             

if(curl_exec($ch) === false)
{
    echo 'Curl error: ' . curl_error($ch);
}                                                                                                      
$errors = curl_error($ch);                                                                                                            
$result = curl_exec($ch);
$returnCode = (int)curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);  
echo $returnCode;
var_dump($errors);
print_r(json_decode($result, true));
于 2017-04-20T05:53:13.390 回答
7

基本方法的其他方法是:

$curl = curl_init();

$public_key = "public_key";
$private_key = "private_key";

curl_setopt_array($curl, array(
CURLOPT_URL => "https://url.endpoint.co/login",
CURLOPT_RETURNTRANSFER => true,
CURLOPT_ENCODING => "",
CURLOPT_MAXREDIRS => 10,
CURLOPT_TIMEOUT => 0,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST => "POST",
CURLOPT_HTTPHEADER => array(
"Content-Type: application/json",
"Authorization: Basic ".base64_encode($public_key.":".$private_key)
),
));
$response = curl_exec($curl);
curl_close($curl);
echo $response;
于 2020-09-10T12:43:41.303 回答
6

对于那些不想使用 curl 的人:

//url
$url = 'some_url'; 

//Credentials
$client_id  = "";
$client_pass= ""; 

//HTTP options
$opts = array('http' =>
    array(
        'method'    => 'POST',
        'header'    => array ('Content-type: application/json', 'Authorization: Basic '.base64_encode("$client_id:$client_pass")),
        'content' => "some_content"
    )
);

//Do request
$context = stream_context_create($opts);
$json = file_get_contents($url, false, $context);

$result = json_decode($json, true);
if(json_last_error() != JSON_ERROR_NONE){
    return null;
}

print_r($result);
于 2018-09-24T11:31:10.953 回答
4

雅虎有一个使用 PHP 调用他们的 REST 服务的教程:

制作雅虎!使用 PHP 的 Web 服务 REST 调用

我自己没有使用过它,但雅虎就是雅虎,至少应该保证一定程度的质量。不过,它们似乎没有涵盖 PUT 和 DELETE 请求。

此外,curl_exec() 和其他人的用户贡献的注释包含许多有用的信息。

于 2010-01-26T15:46:06.687 回答
3

Michael Dowling 非常积极维护的Guzzle是一个不错的选择。除了优雅的界面、异步调用和 PSR 合规性之外,它还使 REST 调用的身份验证标头变得非常简单:

// Create a client with a base URL
$client = new GuzzleHttp\Client(['base_url' => 'http://myservices.io']);

// Send a request to http://myservices.io/status with basic authentication
$response = $client->get('/status', ['auth' => ['username', 'password']]);

请参阅文档

于 2016-08-12T06:14:06.060 回答
-7

有多个 REST 框架。我强烈建议您研究PHP 的 Slim 迷你框架
是其他列表。

于 2015-08-30T07:27:52.393 回答