python - 用于映射拼字游戏字母分布的 dict 理解

Question

我有一个清单：

scrabble_scores = [(1, "E A O I N R T L S U"), (2, "D G"), (3, "B C M P"),
               (4, "F H V W Y"), (5, "K"), (8, "J X"), (10, "Q Z")]

每当通过上述列表时，我必须编写一个函数，该函数给出一个包含一个字母到分数映射的字典。请帮助我编写函数...！

Answer 1

for有两个循环的字典理解：

letter_score = {letter: score for score, letters in scrabble_scores
                              for letter in letters.split()}

例如，对于字符串中的每个字母（由空格分隔），在输出字典中生成一个键值对；关键是字母，值是分数。

演示：

>>> scrabble_scores = [(1, "E A O I N R T L S U"), (2, "D G"), (3, "B C M P"),
...                (4, "F H V W Y"), (5, "K"), (8, "J X"), (10, "Q Z")]
>>> letter_score = {letter: score for score, letters in scrabble_scores
...                               for letter in letters.split()}
>>> letter_score
{'A': 1, 'C': 3, 'B': 3, 'E': 1, 'D': 2, 'G': 2, 'F': 4, 'I': 1, 'H': 4, 'K': 5, 'J': 8, 'M': 3, 'L': 1, 'O': 1, 'N': 1, 'Q': 10, 'P': 3, 'S': 1, 'R': 1, 'U': 1, 'T': 1, 'W': 4, 'V': 4, 'Y': 4, 'X': 8, 'Z': 10}
>>> letter_score['Q']
10

奖金词得分计算器：

>>> word = 'QUICK'
>>> sum(letter_score[c] for c in word)
20

其中word是仅包含（拼字游戏）字母的大写字符串，忽略双字母和三字母评分。

Answer 2

另一种更详细的方式：

def makeScoreDict(scrabble_scores):
        score_dict = {}
        for row in scrabble_scores:
            for letter in row[1].split():
                score_dict[letter] = row[0]
        return score_dict

Answer 3

这是你想要的吗？好像是你描述的。

scrabble_scores = [(1, "E A O I N R T L S U"), (2, "D G"), (3, "B C M P"),
               (4, "F H V W Y"), (5, "K"), (8, "J X"), (10, "Q Z")]
out_dict = {} 
for score in scrabble_scores:
    val = score[0]
    for letter in score[1].split():
        out_dict[letter] = val
print out_dict

Answer 4

一个非字典理解的答案。

scrabble_scores = [(1, "E A O I N R T L S U"), (2, "D G"), (3, "B C M P"),
           (4, "F H V W Y"), (5, "K"), (8, "J X"), (10, "Q Z")]

d = dict()
for value,letters in scrabble_scores:
    d.update(dict(zip(letters.split(),[value]*len(letters.split())))

我肯定也会把它作为一个 dict comp 来做，我确信这就是 OP 的目的，但这dict(zip(iter,iter))是一个值得一提的有用表达。

Answer 5

在 python 中，您可以像这样循环对：

for score, letters in scrabble_scores:
    print("{}: {}".format(letters, score))

这将给出结果：

"E A O I N R T L S U": 1
"D G": 2
...

在 python 中，您可以在这些空格上拆分包含空格的字符串：

>>> "E A O I N R T L S U".split()
['E', 'A', 'O', 'I', 'N', 'R', 'T', 'L', 'S', 'U']

现在只需将两者结合起来：

for score, letters in scrabble_scores:
    for letter in letters.split():
        # voila, you've got score and letter.