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我怎样才能简化这个查询，只运行一次。我当前的代码：

    int year = 2014;

    Query q = entityManager.createQuery("SELECT   SUM(s.revenue),SUM(s.mediaSpending),SUM(s.grossProfit) FROM Sale s WHERE YEAR(s.date) = :year AND QUARTER(s.date) = :quarter");
    q.setParameter("year", year);

    q.setParameter("quarter", 1);
    Object[] q1 = (Object[]) q.getSingleResult();

    q.setParameter("quarter", 2);
    Object[] q2 = (Object[]) q.getSingleResult();

    q.setParameter("quarter", 3);
    Object[] q3 = (Object[]) q.getSingleResult();

    q.setParameter("quarter", 4);
    Object[] q4 = (Object[]) q.getSingleResult();

我可以以某种方式一次查询所有 4 个 qartal 的列表吗？像这样的东西：

Query q = entityManager.createQuery("SELECT   SUM(s.revenue),SUM(s.mediaSpending),SUM(s.grossProfit) FROM Sale s WHERE YEAR(s.date) = :year AND QUARTER(s.date) =  ???(1-4)");

List<Object[]> q1 =  q.getResultList();

编辑：结果应该是 4 个 Object 的列表：

List{Q1Statistic, Q2Statistic, Q3Statistic, Q4Statistic}
4

1 回答 1

1

是的，您可以尝试以下代码

Session session = entityManager.unwrap(Session.class);
Query query = session.createQuery("SELECT SUM(s.revenue),SUM(s.mediaSpending),SUM(s.grossProfit) FROM Sale s WHERE YEAR(s.date) = :year AND QUARTER(s.date) = :quarter");
query.setParameter("year", year);
query.setParameter("quarter", 1);
List<Object[]> result = query.list();

也看看Hibernate SessionFactory vs. EntityManagerFactory

编辑

看起来问题出在您的查询中尝试以下查询希望这对您有所帮助

询问

SELECT SUM(s.revenue),SUM(s.mediaSpending),SUM(s.grossProfit) FROM Sale s 
WHERE YEAR(s.date) = :year 
GROUP BY YEAR(s.date) , QUARTER(s.date)
于 2014-01-23T11:20:59.310 回答