0

我正在尝试将以下 XML 生成为表的列：

<root>
    <Address1>
        <Addressline1>Test Road</Addressline1>
        <Addressline2>Test Street</Addressline2>
        <Addressline3>Test Town</Addressline3>
        <Addressline4>Test State</Addressline4>
        <Postcode>Test Postcode</Postcode>
    </Address1>
    <Address2>
        <Addressline1>Test Road</Addressline1>
        <Addressline2>Test Street</Addressline2>
        <Addressline3>Test Town</Addressline3>
        <Addressline4>Test State</Addressline4>
        <Postcode>Test Postcode</Postcode>
    </Address2>
</root>

我几乎可以使用以下 SQL：

select  (1Addressline1,
        1Addressline2,
        1Addressline3,
        1Addressline4,
        1Postcode for xml path('Address'), root('Addresses')) AS Address1,
        (2Addressline1,
        2Addressline2,
        2Addressline3,
        2Addressline4,
        2Postcode for xml path('Address'), root('Addresses')) AS Address2,
        ColumnA
        ColumnB
        ColumnC
From    Addresses

这会产生以下 XML：

<root>
    <Address1>
        <Addressline1>Test Road</Addressline1>
        <Addressline2>Test Street</Addressline2>
        <Addressline3>Test Town</Addressline3>
        <Addressline4>Test State</Addressline4>
        <Postcode>Test Postcode</Postcode>
    </Address1>
</root>,    
<root>
    <Address2>
        <Addressline1>Test Road</Addressline1>
        <Addressline2>Test Street</Addressline2>
        <Addressline3>Test Town</Addressline3>
        <Addressline4>Test State</Addressline4>
        <Postcode>Test Postcode</Postcode>
    </Address2>
</root>,    
ColumnA,
ColumnB,
ColumnC

不正确的是生成两个单独的 XML 列。我现在需要像上面那样在根节点下组合 Address1 和 Address 2，但无法解决或找到正确的语法。

编辑：正如建议的那样，我已将我的代码修改为这给出了许多语法错误：

SELECT      ColumnA,
            ColumnB,
            ColumnC,

            (
                select
                (
                    (
                        select      RTRIM(Address1Line1),
                                    RTRIM(Address1Line2),
                                    RTRIM(Address1Line3),
                                    RTRIM(Address1Line4),
                                    RTRIM(Address1Line5) 
                        for xml path('Address'), type
                    ),
                    (
                        select      RTRIM(Address2Line1),
                                    RTRIM(Address2Line2),
                                    RTRIM(Address2Line3),
                                    RTRIM(Address2Line4),
                                    RTRIM(Address2Line5)
                        for xml path('Address'), type
                    )
                ) FOR XML PATH(''), root('Addresses'),type
            ) AS Addresses

FROM        TableA
4

2 回答 2

0

只需将文字替换为表中列的名称：

select
(SELECT '1' addressline1,'2' addressline2, '3' addressline3, '4' addressline4, 'PC' postcode for xml path('Address1'), type ),
(SELECT '21' addressline1,'22' addressline2, '23' addressline3, '24' addressline4, '2PC' postcode for xml path('Address2'), type  )
FOR XML PATH(''), root('PatientAddress'),type
于 2014-01-21T16:07:36.153 回答
0 
DECLARE @Addresses TABLE 
(AddressNumber INT, Addressline1 VARCHAR(50),Addressline2 VARCHAR(50)
,Addressline3 VARCHAR(50),Addressline4 VARCHAR(50),PostCode VARCHAR(50))

INSERT INTO @Addresses VALUES 
(1,'Add 1 Addressline1', 'Add 1 Addressline2', 'Add 1 Addressline3', 'Add 1 Addressline4', 'ABCD132'),
(2,'Add 2 Addressline1', 'Add 2 Addressline2', 'Add 2 Addressline3', 'Add 2 Addressline4', 'JKLM132'),
(3,'Add 3 Addressline1', 'Add 3 Addressline2', 'Add 3 Addressline3', 'Add 3 Addressline4', 'RTPZ132'),
(4,'Add 4 Addressline1', 'Add 4 Addressline2', 'Add 4 Addressline3', 'Add 4 Addressline4', 'XMLO132')


select   AddressNumber [@AddressID]
        ,Addressline1
        ,Addressline2
        ,Addressline3
        ,Addressline4
        ,PostCode
FROM    @Addresses 
for xml PATH('Address'),Elements , root('PatientAddress')

结果集

<PatientAddress>
  <Address AddressID="1">
    <Addressline1>Add 1 Addressline1</Addressline1>
    <Addressline2>Add 1 Addressline2</Addressline2>
    <Addressline3>Add 1 Addressline3</Addressline3>
    <Addressline4>Add 1 Addressline4</Addressline4>
    <PostCode>ABCD132</PostCode>
  </Address>
  <Address AddressID="2">
    <Addressline1>Add 2 Addressline1</Addressline1>
    <Addressline2>Add 2 Addressline2</Addressline2>
    <Addressline3>Add 2 Addressline3</Addressline3>
    <Addressline4>Add 2 Addressline4</Addressline4>
    <PostCode>JKLM132</PostCode>
  </Address>
  <Address AddressID="3">
    <Addressline1>Add 3 Addressline1</Addressline1>
    <Addressline2>Add 3 Addressline2</Addressline2>
    <Addressline3>Add 3 Addressline3</Addressline3>
    <Addressline4>Add 3 Addressline4</Addressline4>
    <PostCode>RTPZ132</PostCode>
  </Address>
  <Address AddressID="4">
    <Addressline1>Add 4 Addressline1</Addressline1>
    <Addressline2>Add 4 Addressline2</Addressline2>
    <Addressline3>Add 4 Addressline3</Addressline3>
    <Addressline4>Add 4 Addressline4</Addressline4>
    <PostCode>XMLO132</PostCode>
  </Address>
</PatientAddress>
于 2014-01-21T15:50:40.933 回答