2

我正在使用 Doctrine、Symfony 2.4、FOSRestBundle 和 JMSBundle 来创建一个简单的 REST api。我创建了一个简单的用户实体和一个控制器来实现 POST 方法（GET 方法工作正常）。当我尝试发布数据时，我的 $user 对象属性始终为空，请求-> 数据上的值没有被反序列化。真的一整天都在与这个作斗争。

我的用户实体：

namespace AbcBank\ApiBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use JMS\Serializer\Annotation as JMS;
use JMS\Serializer\Annotation\Expose;
use JMS\Serializer\Annotation\ExclusionPolicy;
use JMS\Serializer\Annotation\Accessor;

/**
 * User
 *
 * @ORM\Table()
 * @ORM\Entity(repositoryClass="AbcBank\ApiBundle\Entity\UserRepository")
 * @JMS\ExclusionPolicy("all")
 */
class User
{
    /**
     * @var integer
     * 
     * @ORM\Column(name="id", type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     * 
     * @Expose
     * @JMS\Type("integer")
     * @Accessor(getter="getId")
     */
    private $id;

    /**
     * @var string
     * 
     * @ORM\Column(name="username", type="string", length=25)
     * 
     * @Expose
     * @JMS\Type("string")
     */
    private $username;

    /**
     * Get id
     *
     * @return integer 
     */
    public function getId()
    {
        return $this->id;
    }

    /**
     * Set username
     *
     * @param string $username
     * @return User
     */
    public function setUsername($username)
    {
        $this->username = $username;

        return $this;
    }

    /**
     * Get username
     *
     * @return string 
     */
    public function getUsername()
    {
        return $this->username;
    }
}

然后在我的用户控制器 (src/ApiBundle/Controller/UserController.php) 我有： namespace AbcBank\ApiBundle\Controller;

use Symfony\Component\HttpFoundation\Request;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Method;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Template;

use FOS\RestBundle\Controller\FOSRestController;
use FOS\RestBundle\Controller\Annotations\View;
use JMS\Serializer\SerializerBuilder;

use AbcBank\ApiBundle\Entity\User;

/**
 * User controller.
 *
 * @Route("/user")
 */
class UserController extends Controller
{
    //... more code

    /**
     * POST
     * 
     * @param \Symfony\Component\HttpFoundation\Request $request
     * @return FormTypeInterface|View
     */
    public function postUserAction(Request $request)
    {
        $serializer = $this->get('jms_serializer');

        /**
         * deserialize the json content to a User type object
         */
        $content = $request->getContent();
        $user = $serializer->deserialize($content, 'AbcBank\ApiBundle\Entity\User', 'json');

        if ($user instanceof \AbcBank\ApiBundle\Entity\User === false) {
            return View::create(array('errors' => $user), 400);
        }

        /**
         * persist object into the database
         */
        $em = $this->getDoctrine()->getManager();
        $em->persist($user);
        $em->flush();

        $url = $this->generateUrl(
            'user_get',
            array('id' => $user->getId()),
            true
        );

        $response = new Response();
        $response->setStatusCode(201);
        $response->headers->set('Location', $url);

        return $response;   
    }
}

将不胜感激任何帮助.. 非常非常令人沮丧，可能我错过了一些愚蠢的东西..

亲切的问候。

4

2 回答 2

3

这可能是因为序列化程序默认将属性从驼峰式大小写转换为“小写下划线名称”，反序列化时反之。

序列化：myProperty => my_property反序列化：
my_property => myProperty

请参阅@SerializedName的文档

于 2016-01-28T21:15:34.617 回答
0

尝试这个 ：

public function postUserAction(Request $request) {
$serializer = $this->get('jms_serializer');

/**
 * deserialize the json content to a User type object
 */
$content = $request->getContent();
$user = $serializer->deserialize($content, 'AbcBank\ApiBundle\Entity\User', 'json');

if ($user instanceof \AbcBank\ApiBundle\Entity\User === false) {
    return View::create(array('errors' => $user), 400);
}

/**
 * persist object into the database
 */
$em = $this->getDoctrine()->getManager();

$updatedUser = $em->merge($user);

$em->flush();

$url = $this->generateUrl(
    'user_get',
    array('id' => $user->getId()),
    true
);

$response = new Response();
$response->setStatusCode(201);
$response->headers->set('Location', $url);

return $response };
于 2014-02-14T11:07:17.880 回答