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我正在尝试使用 servlet 将文件上传到 WebLogic 服务器。这是 doPost 方法：

    public void doPost(HttpServletRequest request, 
               HttpServletResponse response)
              throws ServletException, java.io.IOException 
{

    boolean isMultipart;
    String filePath=null;
    int maxFileSize = 2 * 1024 * 1024;
    int maxMemSize = 1024 * 1024;
    File file ;

      // Check that we have a file upload request
    isMultipart = ServletFileUpload.isMultipartContent(request);
    response.setContentType("text/html");
    java.io.PrintWriter out = response.getWriter( );
    if( !isMultipart )
    {
         out.println("<html>");
         out.println("<head>");
         out.println("<title>Servlet upload</title>");  
         out.println("</head>");
         out.println("<body>");
         out.println("<p>No file uploaded</p>"); 
         out.println("</body>");
         out.println("</html>");
         return;
      }
      DiskFileItemFactory factory = new DiskFileItemFactory();
      // maximum size that will be stored in memory
      factory.setSizeThreshold(2 * 1024 * 1024);
      // Location to save data that is larger than maxMemSize.
      factory.setRepository(new File("c:\\temp"));

      // Create a new file upload handler
      ServletFileUpload upload = new ServletFileUpload(factory);
      // maximum file size to be uploaded.
      upload.setSizeMax( maxFileSize );

      try{ 
      // Parse the request to get file items.
      List fileItems = upload.parseRequest(request);

      // Process the uploaded file items
      Iterator i = fileItems.iterator();

      out.println("<html>");
      out.println("<head>");
      out.println("<title>Servlet upload</title>");  
      out.println("</head>");
      out.println("<body>");

      while ( i.hasNext () ) 
      {
         FileItem fi = (FileItem)i.next();
         if ( !fi.isFormField () )      
         {
            // Get the uploaded file parameters
            String fieldName = fi.getFieldName();
            String fileName = fi.getName();
                ServletContext context = getServletContext();  
                Connection conn = (Connection)context.getAttribute("DBCON");
                PreparedStatement stmt=null;

                try 
                {
                    stmt=conn.prepareStatement("INSERT INTO emp VALUES(?, ?, ?)");
                    out.println("Created the statement!");
                } 
                catch (SQLException e) 
                {
                    out.println("Unable to create prepared statement because: "+e.getMessage());
                }

                WriteToDB ob=new WriteToDB();
                out.println("CWriting to DB!");
                ob.process("C:\\JDeveloper\\mywork\\App\\Project1\\data" + "\\" + fileName, stmt, out);
                out.println("Wrote to DB!");
            }
         }
      } catch (FileUploadException e) {
    }
    out.println("</body>");
      out.println("</html>");
   }

正如我所读到的，这是 web.xml 的重要部分：

<context-param> 
<description>Location to store uploaded file</description> 
<param-name>file-upload</param-name> 
<param-value>
C:\JDeveloper\mywork\App\Project1\data
 </param-value>

我正在使用 JDeveloper。

我有一个带有表单数据的标准上传 HTML 页面。一切都很好，除了在存储位置找不到该文件，它会引发该异常。请帮忙，谢谢。

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