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我正在使用 Php soap 服务器和使用 jax ws 的 java 客户端。如何在后续请求的soap标头中添加sessionId？它的格式是什么？

到目前为止，我这样做了：

String url = "http://localhost:8888/server/soap/server.php";

    // login

MessageFactory mf = MessageFactory.newInstance();
SOAPMessage request = mf.createMessage();
SOAPPart soapPart = request.getSOAPPart();
MimeHeaders headers = request.getMimeHeaders();
headers.addHeader("SOAPAction", url);              

SOAPEnvelope envelope = soapPart.getEnvelope();
envelope.addNamespaceDeclaration("var", url);        

SOAPBody soapBody = envelope.getBody();
SOAPElement soapBodyElem = soapBody.addChildElement("call", "var");

SOAPElement action = soapBodyElem.addChildElement("action", "var");
action.addTextNode("LOGON");        

SOAPElement params = soapBodyElem.addChildElement("params", "var");       


SOAPElement uid = soapBodyElem.addChildElement("uid ", "var");
uid .addTextNode("tester");

SOAPElement password = soapBodyElem.addChildElement("password ", "var");
password .addTextNode("");

params.addChildElement(uid );
params.addChildElement(password);

request.saveChanges();

    /* Print the request message */
    System.out.print("Request SOAP Message:");
    request.writeTo(System.out);
    System.out.println();

    SOAPMessage response = soapConnection.call(request, url);

上面的请求有效，因为它处于登录阶段并且即将获取会话 ID。但是后续的请求呢？

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1 回答 1

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我找到了解决方案：

获取您登录响应的 cookie 并将其设置在下一个请求中，cookie 内容如下所示：

PHPSESSID=sqv184d99ndodebh4te9lmpji5; path=/

这是代码：

 MimeHeaders session = response.getMimeHeaders();     
 String []cookies = session.getHeader("Set-Cookie");             
 request.getMimeHeaders().addHeader("Cookie", cookies[0]);
于 2014-01-16T02:49:11.020 回答