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这是我的注册表：

class RegistrationForm(forms.Form):
    username = forms.CharField(label='Username', max_length=30)
    email = forms.EmailField(label='Email')
    password1 = forms.CharField(label='Password', widget=forms.PasswordInput())
    password2 = forms.CharField(label='Password (Again)', widget=forms.PasswordInput())

def clean_password2(self):
    if 'password1' in self.cleaned_data:
        password1 = self.cleaned_data['password1']
        password2 = self.cleaned_data['password2']
        if password1 == password2:
            return password2
    raise forms.ValidationError('Passwords do not match.')

def clean_username(self):
    username = self.cleaned_data['username']
    if not re.search(r'^\w+$', username): #checks if all the characters in username are in the regex. If they aren't, it returns None
        raise forms.ValidationError('Username can only contain alphanumeric characters and the underscore.')
    try:
        User.objects.get(username=username) #this raises an ObjectDoesNotExist exception if it doesn't find a user with that username
    except ObjectDoesNotExist:
        return username #if username doesn't exist, this is good. We can create the username
    raise forms.ValidationError('Username is already taken.')

这是我的模板：

{% if form.errors %}

    {% for field in form %}
        {% if field.label_tag == "Password (Again)" %}
            <p>The passwords which you entered did not match.</p>
        {% else %}
            {{ field.label_tag }} : {{ field.errors }}
        {% endif %}
    {% endfor %}
{% endif %}

我基本上想说

The passwords which you entered did not match.

如果 Django 为 password2 字段返回错误。我确实在RegistrationForm中说过

password2 = forms.CharField(label='Password (Again)'

但是 Django 直接进入 else 语句，当它执行该行时

{{ field.label_tag }} : {{ field.errors }}

当我检查网络浏览器时，它说

Password (Again) : This field is required.

所以

field.label_tag

确实等于

"Password (Again)"

正确的？我的怎么来

if field.label_tag == "Password (Again)"

声明不评估为真？

4

1 回答 1

1

您在浏览器中看到的并不是field.label_tag真实的。

实际上field.label_tag是这样的（您可以查看 HTML 源代码）：

<label for="id_password2">Password (Again):</label>

引用一位伟人（和 Django文档）：

{{ field.label_tag }} 字段的标签包含在适当的 HTML 标记中。

此代码应该可以工作：

{% if field.label_tag == '<label for="id_password2">Password (Again):</label>' %}
etc

现在，显然，没有人愿意编写这样的代码。带有 HTML 代码的字符串？来吧，奈杰尔，你比这更好！

这是更好的方法：

{% if field.name == 'password2' %}
etc

实际上，我认为还有更好的方法来处理表单错误。您可以在此处阅读文档。

于 2014-01-15T14:49:02.143 回答