2

我需要以下代码的帮助才能将其从程序更改为准备语句。我会尽力编写代码：

默认程序脚本 MYSQLI 默认

<?php
$conn = mysqli_connect ('localhost', 'gggggg', 'gggggg') ; 
mysqli_select_db ($conn, 'ggggg'); 

$anti_injection = mysqli_real_escape_string($_GET['user']);

$sql = "SELECT * FROM profiles WHERE username =".$anti_injection);
$result = mysqli_query($conn, $query);

while($row = mysqli_fetch_array($sql)) {

$username = stripslashes($row['username']);
$age = stripslashes($row['age']);
$gender = stripslashes($row['gender']);
?>


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>title</title>
</head>

<body>
CUSTOM HTML FOR A NICE DESIGN I WANT TO KEEP THE SAME DESIGN LAYOUT ETC...

    CATEGORY <?php echo $username; ?>
    TITEL <?php echo $age; ?>
    CONTENT <?php echo $sex; ?>

</body>
</html>
<?php
}
?>
#

现在我对声明的更改希望它有效

# 
$query = $sql->prepare("SELECT * FROM profiles WHERE `username`=?")
$prep->bind_param("s",$anti_injection);
$prep->execute();

这就是我在安全模式下对 SELECT 的了解，但是使用 MYSQLI_FETCH_ARRAY 我真的不知道它会起作用，希望如果有机会通过 HTML BODY 页面之间的回声保持脚本的方式我喜欢

关于必须如何完成的一些示例？

4

4 回答 4

1

首先，我强烈建议您不要将程序与对象混合。这样会更快地变得混乱。考虑改用该mysqli对象。

$mysqli = new mysqli('localhost'...);

其次，您已经很接近了，但是正如我所说，您正在混合对象和程序，因此您更改它的方式将不起作用。另外，您在整个地方都在弹跳变量（如果您原始运行更改，它将失败）。假设您切换到上述mysqli对象，您可以执行此操作

$prep = $mysqli->prepare("SELECT * FROM profiles WHERE `username`=?");
$prep->bind_param("s",$anti_injection);
$prep->execute();

现在，下一部分很棘手。您必须mysqlnd安装才能执行此操作，但这是恢复结果的最佳方式。如果你运行它并得到一个关于get_result丢失的错误，你没有运行mysqlnd

$result = $prep->get_result();
while($row = $result->fetch_array()) {
    //Your HTML loop here
}
于 2014-01-13T02:00:49.757 回答
1

我提供了一个基于你的脚本，我已经评论、测试并使用了程序“mysqli”。希望它会澄清一些事情。

<?php
/* (PHP 5.3.18 on XAMPP, windows XP)
 *
 * I will use the procedural 'mysqli' functions in this example as that is
 * what you seem familiar with.
 *
 * However, the 'object oriented' style is preferred currently.
 *
 * It all works fine though :-)
 *
 * I recommend PDO (PHP Data Objects) as the way to go for Database access
 * as it provides a 'common' interface to many database engines.
 */


// this is an example 'select' parameter -- how this value gets set is up to you...
// use a form, get parameter or other, it is not important.

$bindparamUsername = 'user_2'; // example!!!!

// connect to the database...
$dbConnection = mysqli_connect('localhost', 'test', 'test'); // connect
mysqli_select_db($dbConnection, 'testmysql'); // my test database


// the SQL Query...

// the '?' is a placeholder for a value that will be substituted when the query runs.
// Note: the ORDER of the selected Columns is important not the column names.
//
// Note: The number of selected columns is important and must match the number of
// 'result' bind variables used later.

$sql = "SELECT username, age, gender FROM profiles WHERE username = ?";

// DB engine: parse the query into an internal form that it understands
$preparedQuery = mysqli_prepare($dbConnection, $sql);

// bind an actual input PHP variable to the prepared query so the db will have all required values
// when the query is executed.
//
mysqli_stmt_bind_param($preparedQuery, 's', $bindparamUsername);

// run the query...
$success = mysqli_execute($preparedQuery);


// You can only bind which variables to store the result columns in AFTER the query has run!
//

// Now bind where any results from the query will be returned...
// There must be as many 'bind' variables as there are selected columns!
// This is because each column value from the query will be returned into the 
// 'bound' PHP variable. 
//
// Note: You cannot bind to an array. You must bind to an individual PHP variable.
//
// I have kept the same names but they are only of use to you.
$fetchedRow = array( 'username' => null,
                     'age'      => null,
                     'gender'   => null);


/*
 *  Note: order of columns in the query and order of destination variables in the       'bind' statement is important.
 *  
 *  i.e. $fetchedRow[username] could be replaced with variable $firstColumn,
 *       $fetchedRow[age] could be replaces with variable $secondColumn
 *   and so on...  
 *     
 * There must be as many bind variables as there are columns.             
 */   
mysqli_stmt_bind_result($preparedQuery, $fetchedRow['username'],
                                        $fetchedRow['age'],
                                        $fetchedRow['gender']);

 /*
 * Note: if you use the 'Object Oriented' version of 'mysqli': All of this is 'hidden'
 *       but still happens 'behind the scenes'!
 *
 */
?>

<!DOCTYPE html>
<html>
  <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title></title>
  </head>
  <body>
    CUSTOM HTML FOR A NICE DESIGN I WANT TO KEEP THE SAME DESIGN LAYOUT ETC...

    <?php // each 'fetch' updates the $fetchedRow PHP variable... ?>
    <?php while (mysqli_stmt_fetch($preparedQuery)): ?>
      <br />
        CATEGORY <?php echo $fetchedRow['username']; ?>
      <br />
      TITEL <?php echo $fetchedRow['age']; ?> <br />
      CONTENT <?php echo $fetchedRow['gender']; ?> <br />
    <?php endwhile ?>

  </body>
</html>
于 2014-01-13T18:12:59.427 回答
0

如果您正在学习，我鼓励您使用Object Oriented Style

该手册是您可以找到最准确信息的第一个资源。按照你的例子：

$mysqli = new mysqli("example.com", "user", "password", "database");
if ($mysqli->connect_errno) {
    echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}

//Here you avoid the warning undefine variable if $_GET['user'] ins't set
$user = isset($_GET['user']) ? $_GET['user'] : NULL;
$row = array();

//Checking if $user is NULL
if(!empty($user)){
   // Prepared statement, stage 1: prepare 
   if (!($stmt = $mysqli->prepare("SELECT * FROM profiles WHERE `username`=?"))) {
     echo "Prepare failed: (" . $mysqli->errno . ") " . $mysqli->error;
   }
   /* Prepared statement, stage 2: bind and execute */
   if (!$stmt->bind_param("s", $user)) {
     echo "Binding parameters failed: (" . $stmt->errno . ") " . $stmt->error;
   }
   if (!$stmt->execute()) {
     echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
   }
  //Fetching the result
  $res = $stmt->get_result();
  $row = $res->fetch_assoc();
  /* explicit close recommended */
  $stmt->close();
}else{
//do this code if $user is null
}


//Printing out the result
echo '<pre>';
print_r($row);
echo '</pre>';
于 2014-01-13T02:32:29.510 回答
0

你可以那样做

$link = mysqli_connect("localhost", "my_user", "my_password", "db"); //Establishing connection to the database , this is alias of new mysqli('')
$query="SELECT * FROM profiles WHERE `username`=?";
$stmt = $link->prepare($query);
$stmt->bind_param("s",$anti_injection); // binding the parameter to it
$stmt->execute(); //Executing
$result = $stmt->get_result();
while($row = $result->fetch_array(MYSQLI_ASSOC)) // we used MYSQLI_ASSOC flag here you also can use MYSQLI_NUM or MYSQLI_BOTH
{
//Do stuff
}
于 2014-01-13T02:06:01.870 回答