我已经下载了 Vikram Goyal 的代码 - Experiments in Streaming Content in Java ME
但是,当尝试使用模拟器运行应用程序时,在运行 Darwin Stream Server 后,我收到以下错误 -
Midlet->startApp
StreamingDataSource->StreamingDataSource
StreamingDataSource->getContentType
StreamingDataSource->getLocator (locator = rtsp://127.0.0.1/sample_100kbit.avi)
javax.microedition.media.MediaException: Player cannot be created for video/avi
at javax.microedition.media.Manager.createPlayer(), bci=135
- com.iprs.test.Midlet.startApp(Midlet.java:14)
at javax.microedition.midlet.MIDletTunnelImpl.callStartApp(), bci=1
at com.sun.midp.midlet.MIDletPeer.startApp(), bci=5
at com.sun.midp.midlet.MIDletStateHandler.startSuite(), bci=261
at com.sun.midp.main.AbstractMIDletSuiteLoader.startSuite(), bci=38
at com.sun.midp.main.CldcMIDletSuiteLoader.startSuite(), bci=5
at com.sun.midp.main.AbstractMIDletSuiteLoader.runMIDletSuite(), bci=144
at com.sun.midp.main.AppIsolateMIDletSuiteLoader.main(), bci=26
Midlet->destroyApp
这是 StartApp 方法 -
public void startApp() {
try {
System.out.println("Midlet->startApp");
// create Player instance, realize it and then try to start it
Player player = Manager.createPlayer(new StreamingDataSource("rtsp://127.0.0.1/sample_100kbit.avi")); //(new StreamingDataSource("rtsp://localhost:554/tuner1.wav")); //sample.mp3")); //sample_100kbit.mp4"));
player.realize();
player.start();
} catch(Exception e) {
e.printStackTrace();
}
}
我尝试了一些媒体类型,但我得到了错误。如何解决?谢谢,埃亚尔。