我有一个显示在弹出窗口中的 gridView(gridview 处于透明布局中,它继承自 linearlayout 并且只有部分透明的背景)。我永远无法执行此 GridView 的 OnItemClick。当我在 gridview 中触摸图像时,它似乎被单击(图像 bachgrond 更改),但未调用 OnItemClick。
下面是我的适配器和包含 gridView 的弹出视图的代码。谢谢!
//Adapter
公共类 ImageAdapter 扩展 BaseAdapter { 私有上下文 mContext; 私人 int 项目背景;
public ImageAdapter(Context c) {
mContext = c;
//---setting the style---
TypedArray a = c.obtainStyledAttributes(R.styleable.Gallery1);
itemBackground = a.getResourceId(R.styleable.Gallery1_android_galleryItemBackground, 0);
a.recycle();
}
……
public View getView(int position, View convertView, ViewGroup parent) {
ImageView imageView;
if (convertView == null) {
imageView = new ImageView(mContext);
} else {
imageView = (ImageView) convertView;
}
imageView.setImageResource(images[position]);
imageView.setScaleType(ImageView.ScaleType.CENTER_INSIDE);
imageView.setBackgroundResource(itemBackground);
return imageView;
}
public Integer[] images = {
R.drawable.sound1,
R.drawable.sound2,
R.drawable.sound3,
R.drawable.sound4
};
}
//////////In Activity, onCreate////////
...
final LayoutInflater inflater=(LayoutInflater)this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
final TransparentLayout musicGrid = (TransparentLayout) inflater.inflate(R.layout.gridviewpopup, null, false);
final GridView gView = (GridView) musicGrid.findViewById(R.id.music_gridview);
gView.setAdapter(new ImageAdapter(this));
final PopupWindow soundSelectorWindow = new PopupWindow(this);
soundSelectorWindow.setContentView(musicGrid);
soundSelectorWindow.setTouchable(true);
gView.setOnItemClickListener(new OnItemClickListener()
{
public void onItemClick(AdapterView<?> parent, View v, int position, long id)
{
//NEVER GETS HERE
soundSelectorWindow.dismiss();
}
});