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嗨,我有以下 5 个 mysql 查询,我想通过执行单个查询来查看所有查询的输出。
请让我知道如何加入所有这些查询。

1.

select sum(msu) 
from wgr_raw 
where dt 
between '2013-11-01' and '2013-11-07';

2.

select * 
from wgr_raw 
where dt 
between '2013-11-01' and '2013-11-07' 
order by dt;  

3.

select admin,sum(msu) 
from wgr_raw 
where dt 
between '2013-11-01' and '2013-11-07' 
group by admin;  

4.

SELECT admin, sum(msu) 
from wgr_raw 
where dt 
between '2013-11-01' and '2013-11-07' 
group by admin 
order by msu desc 
limit 25; 

Select ADMIN1,WEEK1,WEEK2,WEEK3,
       (((WEEK3-WEEK2)/WEEK2)*100) as percentage_change, 
         (WEEK3-WEEK2) as MSU_Difference 
from 
       ((select admin as ADMIN1, sum(msu) as WEEK1 
         from wgr_raw 
         where dt >= date_sub(date('2013-11-01'), 
             INTERVAL 25 DAY) and dt < date_sub(date('2013-11-07'), 
             INTERVAL 18 DAY) 
         group by admin 
         order by WEEK1) as q1,
       (select admin as ADMIN2, sum(msu) as WEEK2 
        from wgr_raw 
        where dt >= date_sub(date('2013-11-01'), 
             INTERVAL 18 DAY) and dt < date_sub(date('2013-11-07'), 
             INTERVAL 11 DAY) 
         group by admin 
         order by WEEK2) as q2,
       (select admin as ADMIN3, sum(msu) as WEEK3 
        from wgr_raw where dt >= date_sub(date('2013-11-01'), 
             INTERVAL 11 DAY) and dt < date_sub(date('2013-11-07'), 
             INTERVAL 4 DAY) 
         group by admin 
         order by WEEK3) as q3)  
where ADMIN1=ADMIN3 and ADMIN2=ADMIN3 
group by admin1 
order by WEEK1 desc 
limit 25;  

5.

select dt,sum(msu) 
from wgr_raw 
where dt >= date_sub(date('2013-11-01'), 
   INTERVAL 11 DAY) 
group by dt 
limit 7;  
4

1 回答 1

1

您可以使用合并 n 个选择查询,UNION但 UNION 中有一个条件。您的所有选择字段应该相同,并且 order by 将是常见的。

(
    (SELECT a, b FROM tbl WHERE id >= 50 and id <= 100)
    UNION
    (SELECT a, b FROM tbl WHERE id >= 150 and id <= 200)
    UNION
    (SELECT a, b FROM tbl WHERE id >= 250 and id <= 300)
    UNION
    (SELECT a, b FROM tbl WHERE id >= 350 and id <= 400)

)
ORDER BY a
于 2017-11-02T13:14:30.980 回答