我会做这样的事情:
gsub("[.]?(alpha)[.]?", ".\\1.", c("10-alpha-epoxy-Amorph-4-ene",
".alpha.-cadolene", "alpha.-cadolene",
".alpha-cadolene"
))
[1] "10-.alpha.-epoxy-Amorph-4-ene" ".alpha.-cadolene"
".alpha.-cadolene" ".alpha.-cadolene"
编辑对许多术语的概括:
如果您有术语列表,则可以使用 create tour 正则表达式paste
:
terms <- c('alpha','gamma','beta','delta')
gsub(paste0("[.]?(",paste0(terms,collapse='|'),")[.]?"), ".\\1.",
c("10-alpha-epoxy-Amorph-4-ene",
".gamma.-cadolene", "beta.-cadolene",
".delta-cadolene"))
[1] "10-.alpha.-epoxy-Amorph-4-ene" ".gamma.-cadolene"
".beta.-cadolene"
[4] ".delta.-cadolene"
编辑以全信形式获取 greels 列表:
library(XML)
dat <- readHTMLTable("http://en.wikipedia.org/wiki/Greek_alphabet",
strinsAsFactors=FALSE)[[2]]
terms <- as.character(dat$V2[-c(1,2)])
[1] "alpha" "beta" "gamma" "delta" "epsilon" "zeta" "eta" "theta" "iota" "kappa" "lambda"
[12] "mu" "Name" "Modern" "nu" "xi" "omicron" "pi" "rho" "sigma" "tau" "upsilon"
[23] "phi" "chi" "psi" "omega"