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我正在创建一个包含大量嵌套查询的 SQL 查询,并且我正在尝试使用 CASE 表达式,但它的行为很奇怪。

这是我目前的查询:

select t.fpl_id, t.team_name,
sum(pf.points)as gwpts,
(
    select sum(transfers_malus)
    from gameweeks
    where gameweeks.team_id = t.id and gameweeks.number = g.number
)as malus,
(
    select sum(points)
    from player_fixtures as pfix
    where gw_number = g.number and pfix.player_id = CASE WHEN minutes_played > 0 THEN g.captain_id ELSE g.vice_captain_id END
)
as cpts,
 (
    select max(web_name)
    from players
    join player_fixtures on players.id = player_fixtures.player_id and gw_number = g.number
    where players.id = CASE WHEN player_fixtures.minutes_played > 0 THEN g.captain_id ELSE g.vice_captain_id END
) as captain_name,
array_agg(p.id) as lineup
from teams as t
join gameweeks as g on t.id  = g.team_id
join gameweeks_players as gp on gp.gameweek_id = g.id
join players as p on gp.player_id = p.id
join player_fixtures as pf on p.id = pf.player_id  and pf.gw_number = g.number
where t.id = 1
group by t.id, g.id
order by g.number asc

我遇到问题的一点是,当我根据“minutes_played”进行案例陈述以查看其中一名球员(队长)是否没有上场时:

(select sum(points)
    from player_fixtures as pfix
    where gw_number = g.number and pfix.player_id = CASE WHEN minutes_played > 0 THEN g.captain_id ELSE g.vice_captain_id END
) as cpts

 (
    select max(web_name)
    from players
    join player_fixtures on players.id = player_fixtures.player_id and gw_number = g.number
    where players.id = CASE WHEN player_fixtures.minutes_played > 0 THEN g.captain_id ELSE g.vice_captain_id END
) as captain_name,

当 minutes_played 确实大于 0 时,一切正常。但是,当它等于 0 时,它不会“返回”任何东西,并且我在行中得到一个 NULL 作为回报。minutes_played 是一个整数,当我在 player_fixtures 上尝试以下脚本时,minutes_played = 0 我的 > 评估有效,我得到正确的“BAD”。

DO LANGUAGE plpgsql $$
    BEGIN
        IF (select minutes_played from player_fixtures where gw_number = 19 and player_id = 266 ) > 0 THEN 
            RAISE NOTICE 'GOOD';
        ELSE
            RAISE NOTICE 'BAD';
        END IF;
    END;
$$;

我在整个数据库方面都很陌生,所以我可能犯了一个菜鸟错误,但过去 6 小时我一直在尝试,但没有任何运气。有人能指出我正确的方向吗?

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1 回答 1

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问题是,当没有匹配的行时,sum()返回 null,并且与 null 的比较永远不会为真。

相反,使用exists(),例如:

where exists(select * from player_fixtures
    where gw_number = 19
    and player_id = 266 
    and minutes_played > 0)

或者您可以if exists(...) then在存储过程中使用。

于 2014-01-03T00:58:55.993 回答