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我使用 social.framework 为 Titanium Appcelerator 创建了共享模块。以下是我的代码:

- (id) Facebook {

//if ([SLComposeViewController isAvailableForServiceType:SLServiceTypeFacebook])
//{
    NSLog(@"Sharing via Facebook", nil);

    SLComposeViewController *fbSheet = [SLComposeViewController composeViewControllerForServiceType:SLServiceTypeFacebook];
    [fbSheet setInitialText: [dictPost valueForKey: @"post"]];
    [fbSheet addURL: [NSURL URLWithString: [dictPost valueForKey: @"link"]]];

    NSLog(@"Sharing via Facebook 2", nil);

    [[TiApp app] showModalController: fbSheet animated: YES];
    NSLog(@"Sharing via Facebook 3", nil);

/*} else {
    UIAlertView *alert = [[[UIAlertView alloc] initWithTitle:@"Facebook" message:@"Post can't be shared. Please check Settings." delegate:nil cancelButtonTitle:@"Ok" otherButtonTitles: nil] autorelease];
    [alert show];
}*/
}

- (id) Tweet {
    SLComposeViewController *tweetSheet = [SLComposeViewController
                                           composeViewControllerForServiceType:SLServiceTypeTwitter];
    [tweetSheet setInitialText: [dictPost valueForKey: @"post"]];
    [[TiApp app] showModalController: tweetSheet animated: YES];
}

- (void) SharePost : (id) args {
    ENSURE_UI_THREAD(SharePost, args);
    ENSURE_UI_THREAD(Tweet, nil);
    ENSURE_UI_THREAD(Facebook, nil);

    NSArray *val = args;
    NSDictionary *dict = [[val objectAtIndex: 0] retain];

    dictPost = [NSDictionary dictionaryWithObjects:[NSArray arrayWithObjects: [dict valueForKey: @"post"], [dict valueForKey: @"link"], [dict valueForKey: @"title"], [dict valueForKey: @"image"], nil] forKeys: [NSArray arrayWithObjects: @"post", @"link", @"title", @"image", nil]];

    if ([[dict valueForKey: @"type"] intValue] == 1) {
        [self Tweet];
    } else if ([[dict valueForKey: @"type"] intValue] == 2) {
        [self Facebook];
    }
}

我只需要打电话SharePost,它会做所有的事情。这是唯一同时在 Twitter 和 Facebook 上共享的代码。但是当我在 Facebook 上分享一些 URL 时,对话框会正确显示,当我选择 时POST,它会在一些(大约 5)秒后给我错误。出现以下错误

无法发布到 Facebook - 无法发送帖子,因为与 Facebook 的连接失败。

And from that error, the same can be posted successfully when "Try Again" is selected. 我在这里附上了截图。

选择共享选项并将 URL 设置为共享时打开的对话框。

选择发布按钮时的错误消息。

如果你们中的任何人有任何线索,请告诉我。

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