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我正在使用 JTS 和 Netbeans 来实现 STRtrees 。我正在尝试为一组点（坐标）构建一个 STRtree。这是我的代码：

package example;

import com.vividsolutions.jts.geom.Coordinate;
import com.vividsolutions.jts.geom.Envelope;
import com.vividsolutions.jts.geom.GeometryFactory;
import com.vividsolutions.jts.geom.Point;
import com.vividsolutions.jts.index.ArrayListVisitor;
import com.vividsolutions.jts.index.strtree.STRtree;
import java.util.List;

public class Example {


public static void main(String[] args) {
    //Getting input from the user as points

    GeometryFactory gf = new GeometryFactory();
    Coordinate coord = new Coordinate( 1, 1 );
    Point point=gf.createPoint( coord );
     coord = new Coordinate( 3,2 );
    Point point2=gf.createPoint( coord );
    coord = new Coordinate( 2,4 );
    Point point3=gf.createPoint( coord );
     coord = new Coordinate( 4,1 );
    Point point4=gf.createPoint( coord );
     coord = new Coordinate( 5,2);
    Point point5=gf.createPoint( coord );
     coord = new Coordinate( 4,5);
    Point point6=gf.createPoint( coord );
    coord = new Coordinate( 3,6 );
    Point point7=gf.createPoint( coord );
     coord = new Coordinate( 1,6 );
    Point point8=gf.createPoint( coord );
     coord = new Coordinate( 6,2 );
    Point point9=gf.createPoint( coord );
     coord = new Coordinate( 7,1 );
    Point point10=gf.createPoint( coord );
    coord = new Coordinate( 6,4 );
    Point point11=gf.createPoint( coord );
     coord = new Coordinate( 9,2);
    Point point12=gf.createPoint( coord );
    coord = new Coordinate( 3,8);
    Point point13=gf.createPoint( coord );
     coord = new Coordinate( 1,7);
    Point point14=gf.createPoint( coord );
    coord = new Coordinate( 3,7 );
    Point point15=gf.createPoint( coord );
     coord = new Coordinate( 5,7 );
    Point point16=gf.createPoint( coord );
    //Building the str object
    STRtree strTree=new STRtree();
    //inserting the points into the tree
    strTree.insert(point.getEnvelopeInternal(), point);
    strTree.insert(point2.getEnvelopeInternal(), point2);
    strTree.insert(point3.getEnvelopeInternal(), point3);
     strTree.insert(point4.getEnvelopeInternal(), point4);
    strTree.insert(point5.getEnvelopeInternal(), point5);
    strTree.insert(point6.getEnvelopeInternal(), point6);
     strTree.insert(point7.getEnvelopeInternal(), point7);
    strTree.insert(point8.getEnvelopeInternal(), point8);
    strTree.insert(point9.getEnvelopeInternal(), point9);
     strTree.insert(point10.getEnvelopeInternal(), point10);
    strTree.insert(point11.getEnvelopeInternal(), point11);
    strTree.insert(point12.getEnvelopeInternal(), point12);
     strTree.insert(point13.getEnvelopeInternal(), point13);
    strTree.insert(point14.getEnvelopeInternal(), point14);
    strTree.insert(point15.getEnvelopeInternal(), point15);
    strTree.insert(point16.getEnvelopeInternal(), point16);
    //Building the tree
    strTree.build();
    Coordinate coord2 = new Coordinate( 0,0 );
    Coordinate coord3 = new Coordinate( 5,5);
     Envelope e1=new Envelope(coord2,coord3);
     List List1 = strTree.query(e1);
     System.out.println(List1);
}
}

代码符合并运行，但我希望这些点按此顺序排序（roots->children->leaves）。但我的输出包含包络区域中的随机点。我哪里做错了？

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1 回答 1

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R-tree存储叶子节点中的所有点。

您要查找的“订单”不存在；所有结果都必须来自叶子。

JTS API 看起来非常昂贵。包裹在信封中的点的坐标。您可能想看看 ELKI，我发现它具有非常高的性能。与流行的看法相反，我发现 ELKI R-trees（至少在 STR 批量加载时）在 32 维上仍然可以很好地工作（流行知识声称 R-trees 最多只能在 10 维上工作）。

于 2014-01-02T11:03:22.793 回答