4

我试图在 TPL 数据流中控制数据流。我有一个非常快的生产者和一个非常慢的消费者。（我的真实代码更复杂，但无论如何，这是一个很好的模型，它重现了问题。）

当我运行它时，代码开始消耗内存，就好像它已经过时了——并且生产者上的输出队列尽可能快地填满。我真正希望看到的是生产者停止运行一段时间，直到消费者有机会要求它。根据我对文档的阅读，这是应该发生的：也就是说，我认为生产者会等到消费者有空间。

显然，情况并非如此。我该如何解决它，以免队列发疯？

using System;
using System.Linq;
using System.Threading.Tasks;
using System.Threading.Tasks.Dataflow;
using System.Threading;

namespace MemoryLeakTestCase
{
    class Program
    {

        static void Main(string[] args)
        {
            var CreateData = new TransformManyBlock<int, string>(ignore =>
            {
                return Enumerable.Range(0, 1000 * 1000 * 1000).Select((s,i) => "Hello, World " + i);
            });

            var ParseFile = new TransformManyBlock<string, string>(fileContent =>
            {
                Thread.Sleep(1000);
                return Enumerable.Range(0, 100).Select((sst, iii) => "Hello, " + iii);
            }, new ExecutionDataflowBlockOptions() { BoundedCapacity = 1000 }
            );

            var EndOfTheLine = new ActionBlock<object>(f =>
                {
                });


            var linkOptions = new DataflowLinkOptions { PropagateCompletion = true, };
            CreateData.LinkTo(ParseFile, linkOptions);
            ParseFile.LinkTo(EndOfTheLine, linkOptions);

            Task t = new Task(() =>
            {
                while (true)
                {
                    Console.WriteLine("CreateData: " + Report(CreateData));
                    Console.WriteLine("ParseData:  " + Report(ParseFile));
                    Console.WriteLine("NullTarget: " +  EndOfTheLine.InputCount );
                    Thread.Sleep(1000);
                }

            });
            t.Start();

            CreateData.SendAsync(0);
            CreateData.Complete();

            EndOfTheLine.Completion.Wait();
        }

        public static string Report<T, U>(TransformManyBlock<T, U> block)
        {
            return String.Format("INPUT: {0}   OUTPUT: {1} ", block.InputCount.ToString().PadLeft(10, ' '), block.OutputCount.ToString().PadLeft(10, ' '));
        }


    }
}
4

1 回答 1

5

通常，在这种情况下你会做的就是设置BoundedCapacity块CreateData。但这在这里行不通，因为TransformManyBlock从BoundedCapacity单个IEnumerable.

相反，您可以做的是创建一个函数，该函数迭代集合并SendAsync()仅在目标可以接受时才用于发送更多数据：

/// <remarks>
/// If iterating data throws an exception, the target block is faulted
/// and the returned Task completes successfully.
/// 
/// Depending on the usage, this might or might not be what you want.
/// </remarks>
public static async Task SendAllAsync<T>(
    this ITargetBlock<T> target, IEnumerable<T> data)
{
    try
    {
        foreach (var item in data)
        {
            await target.SendAsync(item);
        }
    }
    catch (Exception e)
    {
        target.Fault(e);
    }
}

用法：

var data = Enumerable.Range(0, 1000 * 1000 * 1000).Select((s,i) => "Hello, World " + i);
await ParseFile.SendAllAsync(data);
ParseFile.Complete();

如果您仍然希望拥有CreateData与原始代码类似的块，则可以在它们之间有两个 bounded BufferBlocks，SendAllAsync()然后使用Encapsulate()它们使它们看起来像一个块：

/// <remarks>
/// boundedCapacity represents the capacity of the input queue
/// and the output queue separately, not their total.
/// </remarks>
public static IPropagatorBlock<TInput, TOutput>
    CreateBoundedTransformManyBlock<TInput, TOutput>(
    Func<TInput, IEnumerable<TOutput>> transform, int boundedCapacity)
{
    var input = new BufferBlock<TInput>(
        new DataflowBlockOptions { BoundedCapacity = boundedCapacity });
    var output = new BufferBlock<TOutput>(
        new DataflowBlockOptions { BoundedCapacity = boundedCapacity });

    Task.Run(
        async () =>
        {
            try
            {
                while (await input.OutputAvailableAsync())
                {
                    var data = transform(await input.ReceiveAsync());

                    await output.SendAllAsync(data);
                }

                output.Complete();
            }
            catch (Exception e)
            {
                ((IDataflowBlock)input).Fault(e);
                ((IDataflowBlock)output).Fault(e);
            }
        });

    return DataflowBlock.Encapsulate(input, output);
}
于 2013-12-22T13:50:01.437 回答