1

我编写了一个非常短的应用程序，我试图在其中实现以下目标：CheckBox从代码中更改其状态。我已经连接了INotifyPropertyChanged界面并期待看到一些结果，但显然该应用程序什么也没做。数据绑定有问题吗？

窗口1.cs

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Linq;
using System.Text;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using System.Threading;

namespace WpfTEST
{
    /// <summary>
    /// Interaction logic for Window1.xaml
    /// </summary>
    public partial class Window1 : Window, INotifyPropertyChanged
    {
        public Window1()
        {
            InitializeComponent();
            this.Loaded += new RoutedEventHandler(Window1_Loaded);
            this.PropertyChanged += new PropertyChangedEventHandler(Window1_PropertyChanged);
        }

        public bool Flag
        {
            get { return m_flag; }
            set
            {
                m_flag = value; 
                OnPropertyChanged("Flag");
            }
        }

        private bool m_flag = false;

        void Window1_Loaded(object sender, RoutedEventArgs e)
        {
            this.m_cbox.DataContext = this;

            for (int i = 0; i < 1000; i++)
            {
                Flag = (i % 2 == 0);
                Thread.Sleep(200);
            }


        }

        #region INotifyPropertyChanged Members

        public event PropertyChangedEventHandler PropertyChanged;
        public void OnPropertyChanged(string name)
        {
            if (PropertyChanged != null)
                PropertyChanged(this, new PropertyChangedEventArgs(name));
        }
        void Window1_PropertyChanged(object sender, PropertyChangedEventArgs e)
        {

        }

        #endregion
    }
}

Window1.xaml

<Window x:Class="WpfTEST.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Window1" Height="300" Width="300" x:Name="window">
    <Grid>
        <Grid.ColumnDefinitions>
            <ColumnDefinition Width="0.5*" />
            <ColumnDefinition Width="0.5*" />
        </Grid.ColumnDefinitions>
        <Grid.RowDefinitions>
            <RowDefinition Height="0.5*" />
            <RowDefinition Height="0.5*" />
        </Grid.RowDefinitions>
        <CheckBox x:Name="m_cbox" Content="Let's see what happens" Grid.Row="2" Grid.Column="2" Grid.RowSpan="1" Grid.ColumnSpan="1" IsChecked="{Binding Path=Flag, ElementName=window, Mode=TwoWay, UpdateSourceTrigger=PropertyChanged}" />
    </Grid>
</Window>
4

2 回答 2

2

我在您的代码中看到的唯一真正问题是 Loaded 中的睡眠循环。这会导致 UI 线程在循环期间无响应，因为您将 UI 线程置于阻塞状态。

有一种更好的方法可以测试您是否可以从代码中更改标志并触发绑定。向窗口添加一个按钮，将一个单击处理程序连接到该按钮，然后在该单击处理程序中切换Flag- 我对您的原始代码进行了这些修改（并删除了睡眠循环），单击该按钮将复选框的状态切换为你似乎渴望的时尚。

<Window x:Class="WpfTEST.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Window1" Height="300" Width="300" x:Name="window">
    <Grid>
        <Grid.ColumnDefinitions>
            <ColumnDefinition Width="0.5*" />
            <ColumnDefinition Width="0.5*" />
        </Grid.ColumnDefinitions>
        <Grid.RowDefinitions>
            <RowDefinition Height="0.5*" />
            <RowDefinition Height="0.5*" />
        </Grid.RowDefinitions>
        <!-- I added this button: -->
        <Button Click="Button_Click" Grid.Row="0" Grid.Column="0"/>
        <CheckBox x:Name="m_cbox" Content="Let's see what happens" Grid.Row="2" Grid.Column="2" Grid.RowSpan="1" Grid.ColumnSpan="1" IsChecked="{Binding Path=Flag, ElementName=window, Mode=TwoWay, UpdateSourceTrigger=PropertyChanged}" />
    </Grid>
</Window>

在后面的代码中：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Linq;
using System.Text;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using System.Threading;

namespace WpfTEST {
    /// <summary>
    /// Interaction logic for Window1.xaml
    /// </summary>
    public partial class Window1 : Window, INotifyPropertyChanged {
        public Window1() {
            InitializeComponent();
            this.Loaded += new RoutedEventHandler(Window1_Loaded);
            this.PropertyChanged += new PropertyChangedEventHandler(Window1_PropertyChanged);
        }

        public bool Flag {
            get { return m_flag; }
            set {
                m_flag = value;
                OnPropertyChanged("Flag");
            }
        }

        private bool m_flag = false;

        void Window1_Loaded( object sender, RoutedEventArgs e ) {
            this.m_cbox.DataContext = this;
            Flag = false;
        }

        #region INotifyPropertyChanged Members

        public event PropertyChangedEventHandler PropertyChanged;
        public void OnPropertyChanged( string name ) {
            if (PropertyChanged != null)
                PropertyChanged(this, new PropertyChangedEventArgs(name));
        }
        void Window1_PropertyChanged( object sender, PropertyChangedEventArgs e ) {

        }

        #endregion

        private void Button_Click( object sender, RoutedEventArgs e ) {
            Flag = !Flag;
        }
    }
}

除了上述修改以添加按钮及其单击处理程序并删除该睡眠循环之外，我没有对您的原始代码进行任何修改（尽管您可以稍微简化一下）。

于 2010-01-14T23:33:21.617 回答
1

仅当您的 Flag 属性是依赖项属性时，这才有效。为了让这个以我能想到的最简单的方式工作，我会做以下事情：将您的绑定更改为：

IsChecked="{绑定路径=标志,模式=TwoWay}"

并在您的代码后面的构造函数中执行此操作：

数据上下文 = 这个；

或在 XAML 中

DataContext="{绑定RelativeSource={RelativeSource self}}"

注意：如果您将数据上下文设置为窗口，则标志不需要是依赖属性。

于 2010-01-14T23:21:57.630 回答