我在同一个 JPanel 上有一个 JButton 和一个 Point(它的运动由跳跃运动控制)。但是,它们与顶部的 JButton 重叠。
有没有办法让我的点在 JPanel 应用程序窗口中始终位于顶部?
这是一个代码片段:
public leapPanel()
{
setLayout(null); //18-12-13
setBackground(Color.WHITE);
setVisible(true); //18-12-13
button = new JButton();
button.setBounds(100, 150, 100, 100);
button.setBackground(Color.BLACK);
add(button);
points[nPoints] = new Point(PWIDTH/2, PHEIGHT/2);
nPoints++;
listener = new leapListener(this);
controller = new Controller();
controller.addListener(listener);
}
public Dimension getPreferredSize()
{
return new Dimension(PWIDTH, PHEIGHT);
}
public void paintComponent(Graphics shape)
{
super.paintComponent(shape);
Graphics2D shaped = (Graphics2D)shape;
shaped.setRenderingHint(RenderingHints.KEY_ANTIALIASING,
RenderingHints.VALUE_ANTIALIAS_ON);
for(int i=0; i<nPoints; i++)
{
shaped.setColor(Color.ORANGE);
shaped.fillOval(points[i].x, points[i].y, 12, 12);
}
}
private Point2D.Float calcScreenNorm(Hand hand, Screen screen)
/* The dot position is calculated using the screen position that the
user's hand is pointing at, which is then normalized to an (x,y)
value between -1 and 1, where (0,0) is the center of the screen.
*/
{
Vector palm = hand.palmPosition();
Vector direction = hand.direction();
Vector intersect = screen.intersect(palm, direction, true);
// intersection is in screen coordinates
// test for NaN (not-a-number) result of intersection
if (Float.isNaN(intersect.getX()) || Float.isNaN(intersect.getY()))
return null;
float xNorm = (Math.min(1, Math.max(0, intersect.getX())) - 0.5f)*2; // constrain to -1 -- 1
float yNorm = (Math.min(1, Math.max(0, (1-intersect.getY()))) - 0.5f)*2;
return new Point2D.Float(xNorm, yNorm);
} // end of calcScreenNorm()