python - 正则表达式模式以匹配未被特定字符包围的字符

Answer 1

Answer 2

Using a negative-lookahead:

regex = r '"(?!<|\s)'

| means "or"
\s means whitespace

You don't need to capture, since you know you're only matching a ".

Alternatively, you could use a character class instead of the or, ie: [<\s].