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我有一个压缩文件的功能和另一个解压缩它的功能。当我尝试解压缩使用自己的函数生成的存档时，会出现空指针异常，因为它没有找到 ZipEntry... 当我尝试使用我的 dezip 函数解压缩使用 winzip 制作的存档时，它可以.

但是我可以用winzip打开和解压缩我的程序生成的档案，文件“内容”在这里，它的内容是好的。仅当我使用解压缩功能尝试时才会出现错误！

这是代码：

public static void zip() {
        try {
            DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
            DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder();
            Document document = documentBuilder.newDocument();

            /* Code to create the xml */

            Properties outFormat = new Properties();
            /* properties */

            TransformerFactory factory = TransformerFactory.newInstance();
            Transformer transformer = factory.newTransformer();
            transformer.setOutputProperties(outFormat);

            ByteArrayOutputStream output = new ByteArrayOutputStream();
            File file = new File("KOKO.zip");
            FileOutputStream foutput = new FileOutputStream(file);

            DOMSource domSource = new DOMSource(document.getDocumentElement());
            StreamResult result = new StreamResult(output);
            transformer.transform(domSource, result);
            output.writeTo(foutput);

            ZipOutputStream zos = new ZipOutputStream(foutput);
            byte[] bytes = output.toByteArray();
            ZipEntry entry = new ZipEntry("content");
            zos.putNextEntry(entry);
            zos.write(bytes);
            zos.closeEntry();
            zos.close();

       /* here the catch clauses */
    }

    public static void unzip(File zipfile, File folder) throws FileNotFoundException, IOException {
        ZipInputStream zis = new ZipInputStream(new FileInputStream(zipfile));
        ZipEntry ze = null;
        try {
            ze = zis.getNextEntry();
            System.out.println("path :"+ zipfile.getAbsolutePath());
            File f = new File(folder.getAbsolutePath(), ze.getName());
            f.getParentFile().mkdirs();
            OutputStream fos = new BufferedOutputStream(new FileOutputStream(f));
            try {
                try {
                    final byte[] buf = new byte[8192];
                    int bytesRead;
                    while (-1 != (bytesRead = zis.read(buf)))
                        fos.write(buf, 0, bytesRead);
                } finally {
                    fos.close();
                }
            } catch (final IOException ioe) {
                f.delete();
                throw ioe;
            }
        } finally {
            zis.close();
        }
    }

谢谢你的帮助

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1 回答 1

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foutput在开始写入之前，您正在写入 zip 文件ZipOutputStream zos

我认为你应该删除行：

output.writeTo(foutput);
于 2013-12-12T11:32:17.850 回答