1

我有这个简单的代码，我确实将一些数据发布到服务器。由于这是在单击时发生的，因此我调用了启动 asyncTask 的函数，如下所示：

save.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {
                    editProfile();
            }
        });

这是我的 editProfile 类：

private void editProfile() {
        Log.v("--", "start");
        final String newAddress = address.getText().toString();
        final String newPhone = phone.getText().toString();
        final String newEmail = email.getText().toString();
        final String newStatus = status.getText().toString();
        final String registerURL = "http://myurl/companyapp/"
                + "user.php?action=edit&user_id=" + userID + "&address="
                + newAddress + "&phone=" + newPhone + "&" + "email=" + newEmail
                + "&status=" + newStatus;
        Log.v("--", registerURL);
        new AsyncTask<Void, Void, Void>() {

            @Override
            protected Void doInBackground(Void... params) {
                HttpClient httpclient = new DefaultHttpClient();
                HttpPost httppost = new HttpPost(registerURL);

                // httppost.setHeader("Accept", "application/json");
                httppost.setHeader("Accept",
                        "application/x-www-form-urlencoded");
                // httppost.setHeader("Content-type",
                // "application/json");
                httppost.setHeader("Content-Type",
                        "application/x-www-form-urlencoded");

                List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(
                        5);
                nameValuePairs.add(new BasicNameValuePair("user_id", userID
                        + ""));
                nameValuePairs
                        .add(new BasicNameValuePair("address", newAddress));
                nameValuePairs.add(new BasicNameValuePair("phone", newPhone));
                nameValuePairs.add(new BasicNameValuePair("email", newEmail));
                nameValuePairs
                        .add(new BasicNameValuePair("status", newStatus));

                try {
                    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs,
                            "UTF-8"));
                } catch (UnsupportedEncodingException e1) {
                    e1.printStackTrace();
                }
                try {
                    HttpResponse response = httpclient.execute(httppost);
                    HttpEntity entity = response.getEntity();
                    test = EntityUtils.toString(entity);
                    if (test.contains("\"success\":true\"")) {
                        Toast.makeText(EditProfile.this,
                                getString(R.string.profile_updated),
                                Toast.LENGTH_SHORT).show();
                        finish();
                    }
                } catch (UnsupportedEncodingException e) {
                    e.printStackTrace();
                } catch (ClientProtocolException e) {
                    e.printStackTrace();
                } catch (IOException e) {
                    e.printStackTrace();
                }
                return null;
            }

        }.execute();
    }

在 logcat 中，我可以看到该函数已被调用，但 asyncTask 不会启动。谁能告诉我为什么会这样？

4

1 回答 1

1

似乎这正在运行，问题出在if(test.contains("\"success\":true\""))- if 语句不正确，所以我可以完成活动

于 2013-12-10T00:10:58.347 回答