我的 google Docs Spreadsheet 调用以 json 格式返回此响应
（我只需要“行”之后的所有内容）请在此处查看格式化响应：）
我使用 php 的json_decode函数来解析数据并使用它（是的，我在 php 方面很糟糕）此代码返回 NULL，根据文档，返回 NULL “如果无法解码 json”。
$json = file_get_contents($jsonurl);
$json_output = json_decode($json);var_dump ($json_output); // 返回 NULL
基本上，我想要完成的是从 Json 响应的第一行值中创建一个简单的数组。
像这样
$array = {'john','John Handcock','email@yahoo.com','2929292','blanc'}
你们是天才，非常感谢您的洞察力和帮助！
回答如下“sberry2A”，响应不是有效的 Json，谷歌为此目的提供了Zend Json 库，但我决定改为解析 tsv-excel 版本:)
您提供的链接中的数据不是有效的 JSON。您提供的似乎是解码版本。你可以看出它不是 JSON，因为数组键没有被引用。例如，版本应该是“版本”。
您的数据应该看起来更像这样
'{"version":"0.6","reqId":"requestIDnumber","status":"ok","sig":"65724392","table":{"cols":[{"id":"A","label":"slug","type":"string", "pattern":""},{"id":"B","label":"name","type":"string","pattern":""},{"id":"C","label":"email","type":"string","pattern":""},{"id":"D","label" :"nsid","type":"number","pattern":"#0.###############"},{"id":"E","label":"theme","type":"string","pattern":""}],"rows":[{"c":[{"v":"mo"},{"v": "Mohammad Taheri"},{"v":"email@yahoo.com"},{"v":"2929292.0","f":"2929292"},{"v":"blanc"}]}]}}'
$json = '{"version":"0.6","reqId":"requestIDnumber","status":"ok","sig":"65724392","table":{"cols":[{"id":"A","label":"slug","type":"string", "pattern":""},{"id":"B","label":"name","type":"string","pattern":""},{"id":"C","label":"email","type":"string","pattern":""},{"id":"D","label" :"nsid","type":"number","pattern":"#0.###############"},{"id":"E","label":"theme","type":"string","pattern":""}],"rows":[{"c":[{"v":"mo"},{"v": "Mohammad Taheri"},{"v":"email@yahoo.com"},{"v":"2929292.0","f":"2929292"},{"v":"blanc"}]}]}}';
$data = json_decode($json);
print_r($data->table->rows);
//输出
Array ( [0] => stdClass Object ( [c] => Array ( [0] => stdClass Object ( [v] => mo ) [1] => stdClass Object ( [v] => Mohammad Taheri ) [2] => stdClass Object ( [v] => email@yahoo.com ) [3] => stdClass Object ( [v] => 2929292.0 [f] => 2929292 ) [4] => stdClass Object ( [v] => blanc ) ) ) )
$json = file_get_contents($jsonfile);
$data = json_decode($json);
print_r($data);
PEAR 包 Services_Json 能够使用不带引号的键解析 JSON。因此，剥离回调并使用 Services_Json 进行解析，我相信这会起作用。
您是否尝试从响应中删除回调函数myData(...)？