1

这个查询有什么问题？

SELECT DISTINCT source, 
                source_description, 
                url 
FROM   staging_census 
WHERE  Trim(Concat(source, source_description, url)) NOT IN (SELECT 
       Trim(Concat(source, 
source_description, url)) 
                                                             FROM   dim_source);

目标是仅提取不存在 Source、Source_Description 和 URL 组合的记录（在我的情况下是这样）。但是，如果它只在一个列中看到匹配项，它会忽略它。

MySQL新手......如果有更好的方法来处理这个查询，我将不胜感激。

4

1 回答 1

2

尝试这个：

SELECT DISTINCT Source, Source_Description, URL
FROM Staging_Census
WHERE CONCAT(TRIM(Source), TRIM(Source_Description0, TRIM(URL))) NOT IN (SELECT CONCAT(TRIM(Source), TRIM(Source_Description0, TRIM(URL))) FROM DIM_Source);

或者 

SELECT DISTINCT SC.Source, SC.Source_Description, SC.URL
FROM Staging_Censusc SC 
LEFT JOIN DIM_Source DS ON (TRIM(SC.Source), TRIM(AC.Source_Description0, TRIM(SC.URL)) = (TRIM(DS.Source), TRIM(DS.Source_Description0, TRIM(DS.URL))
WHERE DS.DimsourceId IS NULL
于 2013-12-06T05:48:55.490 回答