0

所以我有两个查询：

查询一：

SELECT        
a.memno, 
a.name, 
a.addr1, 
a.addr2, 
a.city, 
a.state, 
a.zip, 
a.sex, 
a.lname, 
a.ssan, 
b.addr1 AS old_addr1, 
b.addr2 AS old_addr2, 
b.city AS old_city, 
b.state AS old_state, 
b.zip AS old_zip

FROM            LIB1.TABLE1 a, LIB2.TABLE2 b

WHERE        (a.memno = b.memno) AND 

(b.groupid = 'P2') AND 
(b.type = 'B') AND 
(b.datec = 20131203) AND 
(a.addr1 <> b.addr1) AND 
(a.addr2 <> b.addr2) AND 
(a.city <> b.city) AND 
(a.state <> b.state) AND 
(a.zip <> b.zip)

ORDER BY b.timec DESC

返回 1 条记录。

查询 2：

SELECT        
a.memno, 
a.name, 
a.addr1, 
a.addr2, 
a.city, 
a.state, 
a.zip, 
a.sex, 
a.lname, 
a.ssan, 
b.addr1 AS old_addr1, 
b.addr2 AS old_addr2, 
b.city AS old_city, 
b.state AS old_state, 
b.zip AS old_zip

FROM            LIB2.TABLE1 a, LIB2.TABLE2 b

WHERE        (a.memno = b.memno) AND 
(b.groupid = 'N2') AND 
(b.type = 'B') AND 
(b.datec = 20131203) AND 
(a.addr1 <> b.addr1) AND 
(a.addr2 <> b.addr2) AND 
(a.city <> b.city) AND 
(a.state <> b.state) AND 
(a.zip <> b.zip)

ORDER BY b.timec DESC

返回 2 条记录。

我正在尝试做一个 UNION 让这 2 个查询返回 1 个结果集。

尝试联合：

SELECT        
a.memno, 
a.name, 
a.addr1, 
a.addr2, 
a.city, 
a.state, 
a.zip, 
a.sex, 
a.lname, 
a.ssan, 
b.addr1 AS old_addr1, 
b.addr2 AS old_addr2, 
b.city AS old_city, 
b.state AS old_state, 
b.zip AS old_zip

FROM            LIB1.TABLE1 a, LIB2.TABLE2 b

WHERE        (a.memno = b.memno) AND 

(b.groupid = 'P2') AND 
(b.type = 'B') AND 
(b.datec = 20131203) AND 
(a.addr1 <> b.addr1) AND 
(a.addr2 <> b.addr2) AND 
(a.city <> b.city) AND 
(a.state <> b.state) AND 
(a.zip <> b.zip)

UNION

SELECT        
a.memno, 
a.name, 
a.addr1, 
a.addr2, 
a.city, 
a.state, 
a.zip, 
a.sex, 
a.lname, 
a.ssan, 
b.addr1 AS old_addr1, 
b.addr2 AS old_addr2, 
b.city AS old_city, 
b.state AS old_state, 
b.zip AS old_zip

FROM            LIB2.TABLE1 a, LIB2.TABLE2 b

WHERE        (a.memno = b.memno) AND 
(b.groupid = 'N2') AND 
(b.type = 'B') AND 
(b.datec = 20131203) AND 
(a.addr1 <> b.addr1) AND 
(a.addr2 <> b.addr2) AND 
(a.city <> b.city) AND 
(a.state <> b.state) AND 
(a.zip <> b.zip)

ORDER BY timec DESC

这给了我：

'DESC' 附近的 WHERE 子句出错。无法解析查询文本。

其次是：

SQL 执行错误。

执行的SQL语句：SELECT a.memno, a.name, a.addr1, a.addr2, a.city, a.state, a.zip, a.sex, a.lname, a.ssan, b.addr1 AS old_addr1 , b.addr2 AS old_addr2, b.city AS old_city, b.state AS old_state, b.zip AS old_zip FROM LIB1.TABLE1 a, LIB2.TABLE2 b WHERE (a.mem...

错误来源：CWBODB.DLL

错误消息：错误 [42000][IBM][System i Access ODBC 驱动程序][DB2 for i5/OS]SQL0199 - 不需要关键字 DESC。有效令牌： FOR SKIP WTIH FETCH ORDER UNION EXCEPT OPTIMIZE。

编辑：

Bangs Head不敢相信我错过了在第一次查询结束时仍然有“desc”。在第一个查询结束时去掉“desc”后，我现在得到了同样的错误，但是消息：无法限定 TIMEC 列。

编辑2：

消息：ORDER BY 列 TIMEC 或表达式不在结果表中。

4

2 回答 2

3

联合的第一次查询，你desc在最后一行的末尾离开了：

WHERE a.memno [...snip...] <> b.zipc desc  
                                     ^^^^

...这正是错误消息所说的。仅仅因为您可以DESC在查询末尾看到一个（有效），并不意味着在其他地方不能有一个desc......当您的查询有几英里宽时尤其如此。

于 2013-12-05T19:44:37.997 回答
0

DESC除了第一个子WHERE句中的流氓之外，ORDER BY还应用于结果联合（没有timec列），而不是源数据集。

您可以将这两个查询合并为子查询：

SELECT * FROM
    (SELECT a.memno, a.name, 
            a.addr1, a.addr2, a.city, a.state, a.zip, a.sex, a.lname, a.ssan, 
            b.addr1 as old_addr1, b.addr2 as old_addr2, b.city as old_city, b.state as old_state, b.zip as old_zip 
    FROM LIB1.TABLE1 a, LIB1.TABLE2 b 
    WHERE a.memno = b.memno 
      and b.groupid = 'P2' 
      and b.type = 'B' 
      and b.datec =  20131205 
      AND a.addr1 <> b.addr1 
      AND a.addr2 <> b.addr2 
      AND a.city <> b.city 
      AND a.state <> b.state 
      AND a.zip <> b.zipc 
    ORDER BY b.timec desc  
    ) A
UNION
SELECT * FROM    
    (
    SELECT a.memno, a.name, 
           a.addr1, a.addr2, a.city, a.state, a.zip, a.sex, a.lname, a.ssan, 
           b.addr1 as old_addr1, b.addr2 as old_addr2, b.city as old_city, b.state as old_state, b.zip as old_zip 
    FROM LIB2.TABLE1 a, LIB2.TABLE2 b 
    WHERE a.memno = b.memno 
      and b.groupid = 'N2' 
      and b.type = 'B' 
      and b.datec = 20131205 
      AND a.addr1 <> b.addr1 
      AND a.addr2 <> b.addr2 
      AND a.city <> b.city 
      AND a.state <> b.state 
      AND a.zip <> b.zip 
    ORDER BY b.timec desc
    ) B
于 2013-12-05T19:50:28.627 回答