您可以将json 展开为一条记录,然后根据需要进行查询(请参阅json 函数):
with cte as (
select
race_id,
json_array_elements(r.race_data->'runners') as d,
(r.race_data->>'prize-money')::int as price_money
from races as r
), cte2 as (
select
race_id, price_money,
max(case when (d->>'position')::int = 1 then d->>'name' end) as name1,
max(case when (d->>'position')::int = 2 then d->>'name' end) as name2,
max(case when (d->>'position')::int = 3 then d->>'name' end) as name3
from cte
group by race_id, price_money
)
select *
from cte2
where name1 = 'sam' and name2 = 'john'
sql fiddle demo
由于您的 JSON 结构,这有点复杂。我认为如果你稍微改变一下你的结构,你的查询可能会更简单:
{
"race-time": some-date,
"runners":
{
"1": {"name": "fred","age": 30},
"2": {"name": "sam","age": 31},
"3": {"name": "john","age": 29}
},
"prize-money": 200
}
您可以使用->>
and->
运算符或json_extract_path_text
函数来获取所需的数据,然后在where
子句中使用它:
select *
from races as r
where
r.race_data->'runners'->'1'->>'name' = 'sam';
select *
from races as r
where
json_extract_path_text(r.race_data, 'runners','1','name') = 'sam' and
json_extract_path_text(r.race_data, 'runners','2','name') = 'john';
select *
from races as r
where
(r.race_data->>'prize-money')::int > 100 and
(
select count(*)
from json_each(r.race_data->'runners')
where (value->>'age')::int >= 30
) >= 2
sql fiddle demo