我正在忙于动态生成 mipmap,并使用以下代码阅读这一点:http ://www.g-truc.net/post-0256.html
//Create the mipmapped texture
glGenTextures(1, &ColorbufferName);
glBindTexture(ColorbufferName);
glTexImage2D(GL_TEXTURE_2D, 0, GL_RGB, 512, 512, 0, GL_UNSIGNED_BYTE, NULL);
glGenerateMipmap(GL_TEXTURE_2D); // /!\ Allocate the mipmaps /!\
...
//Create the framebuffer object and attach the mipmapped texture
glBindFramebuffer(GL_FRAMEBUFFER, FramebufferName);
glFramebufferTexture2D(
GL_FRAMEBUFFER, GL_COLOR_ATTACHMENT0, GL_TEXTURE_2D, ColorbufferName, 0);
...
//Commands to actually draw something
render();
...
//Generate the mipmaps of ColorbufferName
glActiveTexture(GL_TEXTURE0);
glBindTexture(GL_TEXTURE_2D, ColorbufferName);
glGenerateMipmap(GL_TEXTURE_2D);
我的问题:
- 为什么
glGenerateMipmap
在渲染到纹理的情况下需要调用两次? - 是否必须每帧都这样调用?
例如,如果我导入漫反射 2d 纹理,则只需在将其加载到 OpenGL 后调用一次,如下所示:
GLCALL(glGenTextures(1, &mTexture));
GLCALL(glBindTexture(GL_TEXTURE_2D, mTexture));
GLint format = (colorFormat == ColorFormat::COLOR_FORMAT_RGB ? GL_RGB : colorFormat == ColorFormat::COLOR_FORMAT_RGBA ? GL_RGBA : GL_RED);
GLCALL(glTexImage2D(GL_TEXTURE_2D, 0, format, textureWidth, textureHeight, 0, format, GL_UNSIGNED_BYTE, &textureData[0]));
GLCALL(glGenerateMipmap(GL_TEXTURE_2D));
GLCALL(glBindTexture(GL_TEXTURE_2D, 0));
我怀疑这是因为纹理每帧都会重绘,并且 mipmap 生成在此过程中使用其内容,但我想确认这一点。
3 - 另外,如果我渲染到我的 gbuffer,然后立即glBlitFramebuffer
将其渲染到默认 FBO,我是否需要绑定并glGenerateMipmap
喜欢这样?
GLCALL(glBindTexture(GL_TEXTURE_2D, mGBufferTextures[GBuffer::GBUFFER_TEXTURE_DIFFUSE]));
GLCALL(glGenerateMipmap(GL_TEXTURE_2D));
GLCALL(glReadBuffer(GL_COLOR_ATTACHMENT0 + GBuffer::GBUFFER_TEXTURE_DIFFUSE));
GLCALL(glBlitFramebuffer(0, 0, mWindowWidth, mWindowHeight, 0, 0, mWindowWidth, mWindowHeight, GL_COLOR_BUFFER_BIT, GL_LINEAR));