我想知道是否可以在 Android 中复制这种图表。
直接从图像输入的数据并不重要，将在前一个屏幕上输入。
如果不可能重新创建一个类似的图表（我认为实际上很难），可以使用一个简单的蜘蛛图，但重要的是可以插入两个不同的系列并且它们有自己的标签。
事实上，请注意大写的标签形成一个表面，而小写的标签将形成另一个。你说你能做到这种事？
我找到了这个库（https://code.google.com/p/charts4j/），他也做图形蜘蛛图，但我不能用他的“传奇”进入不同的系列！
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1 回答
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我已经部分解决了图表的设计！现在我可以画出完全相同的表格并正确输入数据。特别是，我创建了一个扩展 ImageView 和onDraw（Canvas 画布）的自定义视图，我添加了以下代码：（代码根本没有优化，我知道，它只是为了快速运行测试）
@Override
public void onDraw(Canvas canvas) {
super.onDraw(canvas);
Paint paint = new Paint();
Paint paint_cibo = new Paint();
Paint paint_vino = new Paint();
Paint paint_text = new Paint();
final float x = getWidth() * 1.5f;
final float y = getHeight() * 1.5f;
final int[] valori_cibo = new int[]{2, 5, 4, 8, 3, 5};
final int[] valori_vino = new int[]{6, 7, 7, 6, 6, 6};
canvas.drawColor(Color.WHITE);
paint.setAntiAlias(true);
paint.setColor(Color.BLACK);
paint.setStyle(Paint.Style.STROKE);
paint.setStrokeWidth(2f);
paint_cibo.setAntiAlias(true);
paint_cibo.setColor(Color.BLUE);
paint_cibo.setStyle(Paint.Style.STROKE);
paint_cibo.setStrokeWidth(2f);
paint_vino.setAntiAlias(true);
paint_vino.setColor(Color.RED);
paint_vino.setStyle(Paint.Style.STROKE);
paint_vino.setStrokeWidth(2f);
paint_text.setAntiAlias(true);
paint_text.setColor(Color.BLACK);
paint_text.setStyle(Paint.Style.FILL);
paint_text.setTextSize(10);
// Draw the circles
for(int i = 1; i <= 110; i += 10)
canvas.drawCircle(x, y, i, paint);
// Draw the intersection lines
canvas.drawLine(x + 10, y - 2.5f, (float)(x + 10 + 110 * Math.cos(returnGradi(90))), (float)(y - 2.5f - 110 * Math.sin(returnGradi(90))), paint);
canvas.drawLine(x, y, (float)(x + 110 * Math.cos(returnGradi(45))), (float)(y - 110 * Math.sin(returnGradi(45))), paint);
canvas.drawLine(x, y, (float)(x + 110 * Math.cos(returnGradi(30))), (float)(y - 110 * Math.sin(returnGradi(30))), paint);
canvas.drawLine(x + 10, y - 5, (float)(x + 10 + 110 * Math.cos(returnGradi(315))), (float)(y - 5 - 110 * Math.sin(returnGradi(315))), paint);
canvas.drawLine(x, y + 8, (float)(x + 110 * Math.cos(returnGradi(315))), (float)(y + 8 - 110 * Math.sin(returnGradi(315))), paint);
canvas.drawLine(x, y, (float)(x + 110 * Math.cos(returnGradi(280))), (float)(y - 110 * Math.sin(returnGradi(280))), paint);
canvas.drawLine(x, y, (float)(x + 110 * Math.cos(returnGradi(260))), (float)(y - 110 * Math.sin(returnGradi(260))), paint);
canvas.drawLine(x - 10, y - 5, (float)(x - 10 + 110 * Math.cos(returnGradi(225))), (float)(y - 5 - 110 * Math.sin(returnGradi(225))), paint);
canvas.drawLine(x, y + 8, (float)(x + 110 * Math.cos(returnGradi(225))), (float)(y + 8 - 110 * Math.sin(returnGradi(225))), paint);
canvas.drawLine(x - 10, y - 2.5f, (float)(x - 10 + 110 * Math.cos(returnGradi(90))), (float)(y - 2.5f - 110 * Math.sin(returnGradi(90))), paint);
canvas.drawLine(x, y, (float)(x + 110 * Math.cos(returnGradi(135))), (float)(y - 110 * Math.sin(returnGradi(135))), paint);
canvas.drawLine(x, y, (float)(x + 110 * Math.cos(returnGradi(150))), (float)(y - 110 * Math.sin(returnGradi(150))), paint);
// Draw the numbers
for(int i = 1; i <= 10; i++)
canvas.drawText(String.valueOf(i), x - 2.5f, y - i * 10, paint_text);
//Start drawing food
canvas.drawLine((float)(x + valori_cibo[0] * 10 * Math.cos(returnGradi(45))), (float)(y - valori_cibo[0] * 10 * Math.sin(returnGradi(45))), (float)(x + valori_cibo[1] * 10 * Math.cos(returnGradi(30))), (float)(y - valori_cibo[1] * 10 * Math.sin(returnGradi(30))), paint_cibo);
canvas.drawLine((float)(x + valori_cibo[1] * 10 * Math.cos(returnGradi(30))), (float)(y - valori_cibo[1] * 10 * Math.sin(returnGradi(30))), (float)(x + valori_cibo[2] * 10 * Math.cos(returnGradi(280))), (float)(y - valori_cibo[2] * 10 * Math.sin(returnGradi(280))), paint_cibo);
canvas.drawLine((float)(x + valori_cibo[2] * 10 * Math.cos(returnGradi(280))), (float)(y - valori_cibo[2] * 10 * Math.sin(returnGradi(280))), (float)(x + valori_cibo[3] * 10 * Math.cos(returnGradi(260))), (float)(y - valori_cibo[3] * 10 * Math.sin(returnGradi(260))), paint_cibo);
canvas.drawLine((float)(x + valori_cibo[3] * 10 * Math.cos(returnGradi(260))), (float)(y - valori_cibo[3] * 10 * Math.sin(returnGradi(260))), (float)(x + valori_cibo[4] * 10 * Math.cos(returnGradi(150))), (float)(y - valori_cibo[4] * 10 * Math.sin(returnGradi(150))), paint_cibo);
canvas.drawLine((float)(x + valori_cibo[4] * 10 * Math.cos(returnGradi(150))), (float)(y - valori_cibo[4] * 10 * Math.sin(returnGradi(150))), (float)(x + valori_cibo[5] * 10 * Math.cos(returnGradi(135))), (float)(y - valori_cibo[5] * 10 * Math.sin(returnGradi(135))), paint_cibo);
canvas.drawLine((float)(x + valori_cibo[5] * 10 * Math.cos(returnGradi(135))), (float)(y - valori_cibo[5] * 10 * Math.sin(returnGradi(135))), (float)(x + valori_cibo[0] * 10 * Math.cos(returnGradi(45))), (float)(y - valori_cibo[0] * 10 * Math.sin(returnGradi(45))), paint_cibo);
//Start drawing Wine
canvas.drawLine((float)(x + 10 + valori_vino[0] * 10 * Math.cos(returnGradi(90))), (float)(y - valori_vino[0] * 10 * Math.sin(returnGradi(90))), (float)(x + 10 + valori_vino[1] * 10 * Math.cos(returnGradi(315))), (float)(y - 5 - valori_vino[1] * 10 * Math.sin(returnGradi(315))), paint_vino);
canvas.drawLine((float)(x + 10 + valori_vino[1] * 10 * Math.cos(returnGradi(315))), (float)(y - 5 - valori_vino[1] * 10 * Math.sin(returnGradi(315))), (float)(x + 5 + valori_vino[3] * 10 * Math.cos(returnGradi(315))), (float)(y + 10 - valori_vino[3] * 10 * Math.sin(returnGradi(315))), paint_vino);
canvas.drawLine((float)(x + 5 + valori_vino[3] * 10 * Math.cos(returnGradi(315))), (float)(y + 10 - valori_vino[3] * 10 * Math.sin(returnGradi(315))), (float)(x + 5 + valori_vino[3] * 10 * Math.cos(returnGradi(225))), (float)(y + 5 - valori_vino[3] * 10 * Math.sin(returnGradi(225))), paint_vino);
canvas.drawLine((float)(x + 5 + valori_vino[3] * 10 * Math.cos(returnGradi(225))), (float)(y + 5 - valori_vino[3] * 10 * Math.sin(returnGradi(225))), (float)(x - 5 + valori_vino[4] * 10 * Math.cos(returnGradi(225))), (float)(y - 8 - valori_vino[4] * 10 * Math.sin(returnGradi(225))), paint_vino);
canvas.drawLine((float)(x - 5 + valori_vino[4] * 10 * Math.cos(returnGradi(225))), (float)(y - 8 - valori_vino[4] * 10 * Math.sin(returnGradi(225))), (float)(x - 10 + valori_vino[5] * 10 * Math.cos(returnGradi(90))), (float)(y - valori_vino[5] * 10 * Math.sin(returnGradi(90))), paint_vino);
canvas.drawLine((float)(x - 10 + valori_vino[5] * 10 * Math.cos(returnGradi(90))), (float)(y - valori_vino[5] * 10 * Math.sin(returnGradi(90))), (float)(x + 10 + valori_vino[0] * 10 * Math.cos(returnGradi(90))), (float)(y - valori_vino[0] * 10 * Math.sin(returnGradi(90))), paint_vino);
}
我再说一遍，不要考虑优化不佳的代码...... 有可能实现某种缩放，将焦点缩放保持在圆心的中心？
于 2013-12-04T11:19:44.563 回答