1

对于我当前的用例，我正在创建一个 scp 脚本，它将日志文件从一台服务器复制到一台或多台其他服务器。

IE

server1:/my/path1/log-files.* --> log_server1:/log/path1/server1
server1:/my/path2/log-files.* --> log_server2:/log/path/server1
server1:/my/path3/log-files.* --> log_server1:/log/path2/server1

我希望能够在 bash（版本 4）中使用关联数组（数组）进行日志文件配置，并通过将它们的名称放入索引数组来遍历所有 A.数组。

但是我很难理解如何使用变量作为 A. Array 的名称来引用命名的 A. Array。

例子：

#!/bin/bash
# GNU bash, version 4.1.2(1)-release (x86_64-redhat-linux-gnu) from RedHat/CentOS 6.4
declare -A log_server1 log_server2
log_server1=([name]="ls1" [user]="user")
log_server2=([name]="ls2" [user]="user")

declare -A log1 log2 log3
log1=([log_server]="log_server1" [path]="/my/path1" [file]="log-files" [rpath]="/log/path1/server1")
log2=([log_server]="log_server2" [path]="/my/path2" [file]="log-files" [rpath]="/log/path/server1")
log3=([log_server]="log_server1" [path]="/my/path3" [file]="log-files" [rpath]="/log/path2/server1")

logs=(log1 log2 log3)

for log in ${logs[@]}
do
  # How can I now refer to the A. Array by the name of "log1", etc ?
  ...
done
4

2 回答 2

3

您可以使用间接扩展，但它真的很难看！

#!/bin/bash

declare -A log_server1=([name]="ls1" [user]="user")
declare -A log_server2=([name]="ls2" [user]="user")

declare -A log1=([log_server]="log_server1" [path]="/my/path1" [file]="log-files" [rpath]="/log/path1/server1")
declare -A log2=([log_server]="log_server2" [path]="/my/path2" [file]="log-files" [rpath]="/log/path/server1")
declare -A log3=([log_server]="log_server1" [path]="/my/path3" [file]="log-files" [rpath]="/log/path2/server1")

logs=( log1 log2 log3 )

for log in "${logs[@]}"; do
    l_ls=$log[log_server]
    l_p=$log[path]
    l_f=$log[file]
    l_rp=$log[rpath]
    echo "array $log:"
    echo "    log_server => ${!l_ls}"
    echo "    path => ${!l_p}"
    echo "    file => ${!l_f}"
    echo "    rpath => ${!l_rp}"
done

在我上面链接的参考手册部分中，您将阅读：

如果参数的第一个字符是感叹号 ( !)，则引入了变量间接级别。Bash 使用由其余参数形成的变量的值作为变量的名称；然后扩展此变量，并将该值用于替换的其余部分，而不是参数本身的值。这称为间接扩展。例外情况是下面的扩展${!prefix}和${!name[@]}描述。感叹号必须紧跟左大括号以引入间接性。

问题。相反，您为什么不创建关联数组log_server, path,file和,和？如：rpathlog1log2log3

#!/bin/bash

declare -A log_server1=([name]="ls1" [user]="user")
declare -A log_server2=([name]="ls2" [user]="user")

declare -A log_server path file rpath

log_server[log1]="log_server1"
path[log1]="/my/path1"
file[log1]="log-files"
rpath[log1]="/log/path1/server1"

log_server[log2]="log_server2"
path[log2]="/my/path2"
file[log2]="log-files"
rpath[log2]="/log/path/server1"

log_server[log3]="log_server3"
path[log3]="/my/path3"
file[log3]="log-files"
rpath[log3]="/log/path2/server1"

for log in "${!log_server[@]}"; do
    echo "log server $log:"
    echo "    log_server => ${log_server[$log]}"
    echo "    path => ${path[$log]}"
    echo "    file => ${file[$log]}"
    echo "    rpath => ${rpath[$log]}"
done
于 2013-12-01T15:29:41.407 回答
0

提出我自己的答案。我期待一些健康的批评:-) 但是，主要问题是如何使用相同的关联数组，并以统一的方式循环它们。

关于如何实现相同目标的建议将不胜感激：

#!/bin/bash
# GNU bash, version 4.1.2(1)-release (x86_64-redhat-linux-gnu) from RedHat/CentOS 6.4
declare -A log_server1 log_server2
log_server1=([name]="ls1" [user]="user")
log_server2=([name]="ls2" [user]="user")

declare -A clog1 clog2 clog3
clog1=([log_server]="log_server1" [path]="/my/path1" [file]="log-files" [rpath]="/log/path1/server1/")
clog2=([log_server]="log_server2" [path]="/my/path2" [file]="log-files" [rpath]="/log/path/server1/")
clog3=([log_server]="log_server1" [path]="/my/path3" [file]="log-files" [rpath]="/log/path2/server1/")

for log in ${!clog*}
do
    l_ls=$log[log_server] ; l_p=$log[path] ; l_f=$log[file] ; l_rp=$log[rpath]
    l_ls=${!l_ls} ; l_p=${!l_p} ; l_f=${!l_f} ; l_rp=${!l_rp}
    r_n=$l_ls[name] ; r_u=$l_ls[user]
    r_n=${!r_n} ; r_u=${!r_u}
    echo "Array $log:"
    cmd="   scp ${l_p}/${l_f}* ${r_u}@${r_n}:${l_rp}"
    echo "${cmd}"
done

结果：

$./bash-A-Array.sh
Array clog1:
   scp /my/path1/log-files* user@ls1:/log/path1/server1/
Array clog2:
   scp /my/path2/log-files* user@ls2:/log/path/server1/
Array clog3:
   scp /my/path3/log-files* user@ls1:/log/path2/server1/
于 2013-12-01T17:35:41.017 回答