我正在使用 Service Bus 2.1 For Windows Server，并且我有一种异步接收消息的方法。
我的方法的主体是：
var waitTimeout = TimeSpan.FromSeconds(10);
// Declare an action acting as a callback whenever a message arrives on a queue.
AsyncCallback completeReceive = null;
// Declare an action acting as a callback whenever a non-transient exception occurs while receiving or processing messages.
Action<Exception> recoverReceive = null;
// Declare an action responsible for the core operations in the message receive loop.
Action receiveMessage = () =>
{
// Use a retry policy to execute the Receive action in an asynchronous and reliable fashion.
retryPolicy.ExecuteAction(
(cb) => messageReceiver.BeginReceive(waitTimeout, cb, null),
(ar) =>
{
// Make sure we are not told to stop receiving while we were waiting for a new message.
if (!cts.IsCancellationRequested)
{
// Complete the asynchronous operation. This may throw an exception that will be handled internally by retry policy.
BrokeredMessage msg = messageReceiver.EndReceive(ar);
// Check if we actually received any messages.
if (msg != null)
{
// Make sure we are not told to stop receiving while we were waiting for a new message.
if (!cts.IsCancellationRequested)
{
try
{
// Process the received message.
processMessage(msg);
// With PeekLock mode, we should mark the processed message as completed.
if (messageReceiver.Mode == ReceiveMode.PeekLock)
{
// Mark brokered message as completed at which point it's removed from the queue.
msg.SafeComplete();
}
}
catch
{
// With PeekLock mode, we should mark the failed message as abandoned.
if (messageReceiver.Mode == ReceiveMode.PeekLock)
{
// Abandons a brokered message. This will cause Service Bus to unlock the message and make it available
// to be received again, either by the same consumer or by another completing consumer.
msg.SafeAbandon();
}
// Re-throw the exception so that we can report it in the fault handler.
throw;
}
finally
{
// Ensure that any resources allocated by a BrokeredMessage instance are released.
msg.Dispose();
}
}
else
{
// If we were told to stop processing, the current message needs to be unlocked and return back to the queue.
if (messageReceiver.Mode == ReceiveMode.PeekLock)
{
msg.SafeAbandon();
}
}
}
}
// Invoke a custom callback method to indicate that we have completed an iteration in the message receive loop.
completeReceive(ar);
},
() =>
{
},
(ex) =>
{
// Invoke a custom action to indicate that we have encountered an exception and
// need further decision as to whether to continue receiving messages.
recoverReceive(ex);
});
};
// Initialize a custom action acting as a callback whenever a message arrives on a queue.
completeReceive = (ar) =>
{
if (!cts.IsCancellationRequested)
{
// Continue receiving and processing new messages until we are told to stop.
receiveMessage();
}
};
// Initialize a custom action acting as a callback whenever a non-transient exception occurs while receiving or processing messages.
recoverReceive = (ex) =>
{
if (!cts.IsCancellationRequested)
{
// Continue receiving and processing new messages until we are told to stop regardless of any exceptions.
receiveMessage();
}
};
// Start receiving messages asynchronously.
receiveMessage();
由于我已将 dll Microsoft.ServiceBus 更新到 2.1 版（在我使用 1.8 和 2.0 版之前），我每秒都有两个例外：
Microsoft.ServiceBus.dll 中出现“System.ServiceModel.FaultException`1”类型的第一次机会异常 Microsoft.ServiceBus.dll 中出现“System.TimeoutException”类型的第一次机会异常
引发异常的方法是：“EndReceive”和 Microsoft.ServiceBus.Messaging.Sbmp.DuplexRequestBindingElement.DuplexRequestSessionChannel.ThrowIfFaultMessage(Message wcfMessage)
我在互联网上看到了一些帖子，但没有任何答案。有人已经有这个问题了吗？