38

我想向需要身份验证的服务器生成 POST 请求。我尝试使用以下方法：

private synchronized String CreateNewProductPOST (String urlString, String encodedString, String title, String content, Double price, String tags) {

    String data = "product[title]=" + URLEncoder.encode(title) +
                "&product[content]=" + URLEncoder.encode(content) + 
                "&product[price]=" + URLEncoder.encode(price.toString()) +
                "&tags=" + tags;
    try {
        URL url = new URL(urlString);
        URLConnection conn;
        conn = url.openConnection();
        conn.setRequestProperty ("Authorization", "Basic " + encodedString);
        conn.setDoOutput(true);
        conn.setDoInput(true);
        OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
        wr.write(data);
        wr.flush(); 
        // Get the response 
        BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); 
        String line; 
        while ((line = rd.readLine()) != null) { 
            // Process line... 
            } 
        wr.close(); 
        rd.close(); 
        return rd.toString();
    } catch (MalformedURLException e) {

        e.printStackTrace();
        return e.getMessage();
    }
    catch (IOException e) {

        e.printStackTrace();
        return e.getMessage();
    } 
}

但服务器没有收到授权数据。应该添加授权数据的行如下：

conn.setRequestProperty ("Authorization", "Basic " + encodedString);

和线

BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));

还会抛出 IOException。

无论如何，如果有人可以建议对上述逻辑进行任何修复，以便使用带有 UrlConnection 的 POST 启用授权，我将非常感激。

但显然它不能按预期工作，尽管如果对 GET 请求使用相同的逻辑，一切正常。

4

8 回答 8

49

一个很好的例子在这里找到。Powerlord做对了，下面是你需要的 POST HttpURLConnection。

下面是执行此操作的代码，

    URL url = new URL(urlString);
    URLConnection conn = url.openConnection();
    conn.setDoOutput(true);
    conn.setRequestProperty ("Authorization", encodedCredentials);

    OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());

    writer.write(data);
    writer.flush();
    String line;
    BufferedReader reader = new BufferedReader(new 
                                     InputStreamReader(conn.getInputStream()));
    while ((line = reader.readLine()) != null) {
      System.out.println(line);
    }
    writer.close();
    reader.close();

更改URLConnection为HttpURLConnection, 使其成为 POST 请求。

    HttpURLConnection conn = (HttpURLConnection) url.openConnection();
    conn.setRequestMethod("POST");

建议（...在评论中）：

您可能还需要设置这些属性，

conn.setRequestProperty( "Content-type", "application/x-www-form-urlencoded");
conn.setRequestProperty( "Accept", "*/*" );
于 2010-01-08T08:27:19.850 回答
14

我在代码中没有看到您指定这是一个 POST 请求的任何地方。再说一次，你需java.net.HttpURLConnection要这样做。

事实上，我强烈建议使用HttpURLConnection而不是URLConnection, withconn.setRequestMethod("POST");并查看它是否仍然会给您带来问题。

于 2010-01-29T20:39:19.897 回答
6

对外部应用程序（INSTAGRAM）进行 oAuth 身份验证第 3 步“收到代码后获取令牌”只有下面的代码对我有用

还值得一提的是，它对我使用一些本地主机 URL 和一个回调 servlet 配置了名称“web.xml 中的回调和注册的回调 URL：例如 localhost:8084/MyAPP/docs/insta/callback

但是在成功完成身份验证步骤后，使用相同的外部站点“INSTAGRAM”执行标签或媒体的 GET 以使用初始方法检索 JSON 数据不起作用。在我的 servlet 中使用 url 进行 GET，例如 api.instagram.com/v1/tags/MYTAG/media/recent?access_token=MY_TOKEN 只有在此处找到的方法有效

感谢所有贡献者

        URL url = new URL(httpurl);
        HashMap<String, String> params = new HashMap<String, String>();
        params.put("client_id", id);
        params.put("client_secret", secret);
        params.put("grant_type", "authorization_code");
        params.put("redirect_uri", redirect);
        params.put("code", code);  // your INSTAGRAM code received 
        Set set = params.entrySet();
        Iterator i = set.iterator();
        StringBuilder postData = new StringBuilder();
        for (Map.Entry<String, String> param : params.entrySet()) {
            if (postData.length() != 0) {
                postData.append('&');
            }
            postData.append(URLEncoder.encode(param.getKey(), "UTF-8"));
            postData.append('=');
            postData.append(URLEncoder.encode(String.valueOf(param.getValue()), "UTF-8"));
        }
        byte[] postDataBytes = postData.toString().getBytes("UTF-8");

        HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
        conn.setRequestMethod("POST");
        conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
        conn.setRequestProperty("Content-Length", String.valueOf(postDataBytes.length));
        conn.setDoOutput(true);
        conn.getOutputStream().write(postDataBytes);
        BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream(), "UTF-8"));
        StringBuilder builder = new StringBuilder();
        for (String line = null; (line = reader.readLine()) != null;) {
            builder.append(line).append("\n");
        }
        reader.close();
        conn.disconnect();
        System.out.println("INSTAGRAM token returned: "+builder.toString());
于 2014-07-19T02:49:52.440 回答
2

要发送 POST 请求调用：

        connection.setDoOutput(true); // Triggers POST.

如果您想在请求中发送文本，请使用：

        java.io.OutputStreamWriter wr = new java.io.OutputStreamWriter(connection.getOutputStream());
        wr.write(textToSend);
        wr.flush();
于 2014-02-28T09:45:03.263 回答
1

我今天遇到了这个问题，这里发布的解决方案都没有奏效。但是，此处发布的代码适用于POST请求：

// HTTP POST request
private void sendPost() throws Exception {

    String url = "https://selfsolve.apple.com/wcResults.do";
    URL obj = new URL(url);
    HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();

    //add reuqest header
    con.setRequestMethod("POST");
    con.setRequestProperty("User-Agent", USER_AGENT);
    con.setRequestProperty("Accept-Language", "en-US,en;q=0.5");

    String urlParameters = "sn=C02G8416DRJM&cn=&locale=&caller=&num=12345";

    // Send post request
    con.setDoOutput(true);
    DataOutputStream wr = new DataOutputStream(con.getOutputStream());
    wr.writeBytes(urlParameters);
    wr.flush();
    wr.close();

    int responseCode = con.getResponseCode();
    System.out.println("\nSending 'POST' request to URL : " + url);
    System.out.println("Post parameters : " + urlParameters);
    System.out.println("Response Code : " + responseCode);

    BufferedReader in = new BufferedReader(
            new InputStreamReader(con.getInputStream()));
    String inputLine;
    StringBuffer response = new StringBuffer();

    while ((inputLine = in.readLine()) != null) {
        response.append(inputLine);
    }
    in.close();

    //print result
    System.out.println(response.toString());

}

事实证明，问题不在于授权。就我而言，这是一个编码问题。我需要的内容类型是application/json但来自 Java 文档：

static String encode(String s, String enc)
Translates a string into application/x-www-form-urlencoded format using a specific encoding scheme.

编码函数将字符串转换为application/x-www-form-urlencoded。

现在，如果您不设置 Content-Type，您可能会收到 415 Unsupported Media Type 错误。如果你将它设置为application/json或任何不是application/x-www-form-urlencoded 的东西，你会得到一个 IOException。要解决这个问题，只需避免使用 encode 方法。

对于这种特殊情况，以下应该有效：

String data = "product[title]=" + title +
                "&product[content]=" + content + 
                "&product[price]=" + price.toString() +
                "&tags=" + tags;

另一个可能有助于解释为什么在创建缓冲读取器时代码会中断的小信息是因为POST请求实际上仅在调用conn.getInputStream()时才被执行。

于 2014-04-15T03:36:43.987 回答
1

在 API 22 上，BasicNamevalue 对的使用已被弃用，而是使用 HASMAP。要了解有关 HasMap 的更多信息，请访问hasmap developer.android 上的更多信息 

package com.yubraj.sample.datamanager;

import android.content.Context;
import android.os.AsyncTask;
import android.os.Bundle;
import android.text.TextUtils;
import android.util.Log;

import com.yubaraj.sample.utilities.GeneralUtilities;


import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.UnsupportedEncodingException;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLEncoder;
import java.util.HashMap;
import java.util.Map;

import javax.net.ssl.HttpsURLConnection;

/**
 * Created by yubraj on 7/30/15.
 */
public class ServerRequestHandler {
    private static final String TAG = "Server Request";
    OnServerRequestComplete listener;

    public ServerRequestHandler (){

    }
    public void doServerRequest(HashMap<String, String> parameters, String url, int requestType, OnServerRequestComplete listener){

        debug("ServerRequest", "server request called, url  = " + url);
        if(listener != null){
            this.listener = listener;
        }
        try {
            new BackgroundDataSync(getPostDataString(parameters), url, requestType).execute();
            debug(TAG , " asnyc task called");
        } catch (Exception e) {
            e.printStackTrace();
        }

    }
    public void doServerRequest(HashMap<String, String> parameters, String url, int requestType){
        doServerRequest(parameters, url, requestType, null);
    }

    public interface OnServerRequestComplete{
        void onSucess(Bundle bundle);
        void onFailed(int status_code, String mesage, String url);
    }

    public void setOnServerRequestCompleteListener(OnServerRequestComplete listener){
        this.listener = listener;
    }

    private String getPostDataString(HashMap<String, String> params) throws UnsupportedEncodingException {
        StringBuilder result = new StringBuilder();
        boolean first = true;
        for(Map.Entry<String, String> entry : params.entrySet()){
            if (first)
                first = false;
            else
                result.append("&");

            result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
            result.append("=");
            result.append(URLEncoder.encode(entry.getValue(), "UTF-8"));
        }

        return result.toString();
    }

    class BackgroundDataSync extends AsyncTask<String, Void , String>{
        String params;
        String mUrl;
        int request_type;

        public BackgroundDataSync(String params, String url, int request_type){
            this.mUrl = url;
            this.params = params;
            this.request_type = request_type;
        }

        @Override
        protected void onPreExecute() {
            super.onPreExecute();
        }

        @Override
        protected String doInBackground(String... urls) {
            debug(TAG, "in Background, urls = " + urls.length);
            HttpURLConnection connection;
                debug(TAG, "in Background, url = " + mUrl);
                String response = "";
                switch (request_type) {
                    case 1:
                        try {
                            connection = iniitializeHTTPConnection(mUrl, "POST");
                            OutputStream os = connection.getOutputStream();
                            BufferedWriter writer = new BufferedWriter(
                                    new OutputStreamWriter(os, "UTF-8"));
                            writer.write(params);
                            writer.flush();
                            writer.close();
                            os.close();
                            int responseCode = connection.getResponseCode();
                            if (responseCode == HttpsURLConnection.HTTP_OK) {
                           /* String line;
                            BufferedReader br=new BufferedReader(new InputStreamReader(connection.getInputStream()));
                            while ((line=br.readLine()) != null) {
                                response+=line;
                            }*/
                                response = getDataFromInputStream(new InputStreamReader(connection.getInputStream()));
                            } else {
                                response = "";
                            }
                        } catch (IOException e) {
                            e.printStackTrace();
                        }
                        break;
                    case 0:
                        connection = iniitializeHTTPConnection(mUrl, "GET");

                        try {
                            if (connection.getResponseCode() == connection.HTTP_OK) {
                                response = getDataFromInputStream(new InputStreamReader(connection.getInputStream()));
                            }
                        } catch (Exception e) {
                            e.printStackTrace();
                            response = "";
                        }
                        break;
                }
                return response;


        }

        @Override
        protected void onPostExecute(String s) {
            super.onPostExecute(s);
            if(TextUtils.isEmpty(s) || s.length() == 0){
                listener.onFailed(DbConstants.NOT_FOUND, "Data not found", mUrl);
            }
            else{
                Bundle bundle = new Bundle();
                bundle.putInt(DbConstants.STATUS_CODE, DbConstants.HTTP_OK);
                bundle.putString(DbConstants.RESPONSE, s);
                bundle.putString(DbConstants.URL, mUrl);
                listener.onSucess(bundle);
            }
            //System.out.println("Data Obtained = " + s);
        }

        private HttpURLConnection iniitializeHTTPConnection(String url, String requestType) {
            try {
                debug("ServerRequest", "url = " + url + "requestType = " + requestType);
                URL link = new URL(url);
                HttpURLConnection conn = (HttpURLConnection) link.openConnection();
                conn.setRequestMethod(requestType);
                conn.setDoInput(true);
                conn.setDoOutput(true);
                return conn;
            }
            catch(Exception e){
                e.printStackTrace();
            }
            return null;
        }

    }
    private String getDataFromInputStream(InputStreamReader reader){
        String line;
        String response = "";
        try {

            BufferedReader br = new BufferedReader(reader);
            while ((line = br.readLine()) != null) {
                response += line;

                debug("ServerRequest", "response length = " + response.length());
            }
        }
        catch (Exception e){
            e.printStackTrace();
        }
        return response;
    }

    private void debug(String tag, String string) {
        Log.d(tag, string);
    }
}

当您需要通过邮寄或像这样从服务器获取数据时，只需调用该函数

HashMap<String, String>params = new HashMap<String, String>();
                    params.put("action", "request_sample");
                    params.put("name", uname);
                    params.put("message", umsg);
                    params.put("email", getEmailofUser());
                    params.put("type", "bio");
dq.doServerRequest(params, "your_url", DbConstants.METHOD_POST);
                    dq.setOnServerRequestCompleteListener(new ServerRequestHandler.OnServerRequestComplete() {
                        @Override
                        public void onSucess(Bundle bundle) {
                            debug("data", bundle.getString(DbConstants.RESPONSE));
                                                    }

                        @Override
                        public void onFailed(int status_code, String mesage, String url) {
                            debug("sample", mesage);

                        }
                    });

现在完成了。享受吧！！！如果发现任何问题，请评论它。

于 2015-08-02T11:34:46.617 回答
0

HTTP 授权在 GET 和 POST 请求之间没有区别，所以我首先假设还有其他问题。我建议不要直接设置 Authorization 标头，而是使用 java.net.Authorization 类，但我不确定它是否能解决您的问题。也许您的服务器以某种方式配置为需要与发布请求的“基本”不同的授权方案？

于 2010-01-08T12:07:38.967 回答
0

我正在寻找有关如何执行 POST 请求的信息。我需要指定 mi 请求是 POST 请求，因为我正在使用仅使用 POST 方法的 RESTful Web 服务，如果请求未发布，当我尝试执行请求时，我会收到 HTTP 错误 405。我保证我的代码在接下来的操作中没有错：我在我的 Web 服务中创建了一个通过 GET 请求调用的方法，并且我将我的应用程序指向使用该 Web 服务方法并且它可以工作。我的代码是下一个：

    URL server = null;
    URLConnection conexion = null;
    BufferedReader reader = null;
    server = new URL("http://localhost:8089/myApp/resources/webService");
    conexion = server.openConnection();
    reader = new BufferedReader(new InputStreamReader(server.openStream()));
    System.out.println(reader.readLine());
于 2010-01-29T20:18:34.080 回答