2

我有一个小脚本，用于urllib2获取网站内容、查找所有链接标签、在顶部和底部附加一小段 HTML，然后我尝试美化它。它不断返回 TypeError: sequence item 1: expected string, Tag found。我环顾四周，我真的找不到问题。一如既往，任何帮助，非常感谢。

import urllib2
from BeautifulSoup import BeautifulSoup
import re

reddit = 'http://www.reddit.com'
pre = '<html><head><title>Page title</title></head>'
post = '</html>'
site = urllib2.urlopen(reddit)
html=site.read()
soup = BeautifulSoup(html)
tags = soup.findAll('a')
tags.insert(0,pre)
tags.append(post)
soup1 = BeautifulSoup(''.join(tags))
print soup1.prettify()

这是追溯：

Traceback (most recent call last): File "C:\Python26\bea.py", line 21, in <module>
        soup1 = BeautifulSoup(''.join(tags))
TypeError: sequence item 1: expected string, Tag found
4

3 回答 3

2

这对我有用：

soup1 = BeautifulSoup(''.join(str(t) for t in tags))

这个 pyparsing 解决方案也提供了一些不错的输出：

from pyparsing import makeHTMLTags, originalTextFor, SkipTo, Combine

# makeHTMLTags defines HTML tag patterns for given tag string
aTag,aEnd = makeHTMLTags("A")

# makeHTMLTags by default returns a structure containing
# the tag's attributes - we just want the original input text
aTag = originalTextFor(aTag)
aEnd = originalTextFor(aEnd)

# define an expression for a full link, and use a parse action to
# combine the returned tokens into a single string
aLink = aTag + SkipTo(aEnd) + aEnd
aLink.setParseAction(lambda tokens : ''.join(tokens))

# extract links from the input html
links = aLink.searchString(html)

# build list of strings for output
out = []
out.append(pre)
out.extend(['  '+lnk[0] for lnk in links])
out.append(post)

print '\n'.join(out)

印刷：

<html><head><title>Page title</title></head>
  <a href="http://www.reddit.com/r/pics/" >pics</a>
  <a href="http://www.reddit.com/r/reddit.com/" >reddit.com</a>
  <a href="http://www.reddit.com/r/politics/" >politics</a>
  <a href="http://www.reddit.com/r/funny/" >funny</a>
  <a href="http://www.reddit.com/r/AskReddit/" >AskReddit</a>
  <a href="http://www.reddit.com/r/WTF/" >WTF</a>
  .
  .
  .
  <a href="http://reddit.com/help/privacypolicy" >Privacy Policy</a>
  <a href="#" onclick="return hidecover(this)">close this window</a>
  <a href="http://www.reddit.com/feedback" >volunteer to translate</a>
  <a href="#" onclick="return hidecover(this)">close this window</a>
</html>
于 2010-01-07T23:55:27.350 回答
0 
soup1 = BeautifulSoup(''.join(unicode(tag) for tag in tags))
于 2010-01-07T16:59:04.727 回答
0

乔纳森的回答有点语法错误，这是正确的：

    soup1 = BeautifulSoup(''.join([unicode(tag) for tag in tags]))
于 2011-06-08T15:32:06.497 回答