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我是 python 新手,我正在尝试测试 gevent-socketio 示例,但没有运气。每次访问 html 文件时都会出现此错误。在这种情况下,我发布了报告的错误,live_cpu_graphchat有同样的问题。

谢谢您的帮助

Listening on port http://0.0.0.0:8080 and on port 10843 (flash policy server)
DEPRECATION WARNING: use `namespace` instead of `resource`
Traceback (most recent call last):
  File "/usr/local/lib/python2.7/dist-packages/gevent/greenlet.py", line 390, in run
    result = self._run(*self.args, **self.kwargs)
  File "/usr/local/lib/python2.7/dist-packages/gevent/server.py", line 159, in wrap_socket_and_handle
    ssl_socket = self.wrap_socket(client_socket, **self.ssl_args)
TypeError: wrap_socket() got an unexpected keyword argument 'policy_listener'
<Greenlet at 0x1cceb90: <bound method SocketIOServer.wrap_socket_and_handle of <SocketIOServer at 0x1dc0710 fileno=3 address=0.0.0.0:8080>>(<socket at 0x1dc08d0 fileno=10 sock=127.0.0.1:8080, ('127.0.0.1', 45823))> failed with TypeError

Traceback (most recent call last):
  File "/usr/local/lib/python2.7/dist-packages/gevent/greenlet.py", line 390, in run
    result = self._run(*self.args, **self.kwargs)
  File "/usr/local/lib/python2.7/dist-packages/gevent/server.py", line 159, in wrap_socket_and_handle
    ssl_socket = self.wrap_socket(client_socket, **self.ssl_args)
TypeError: wrap_socket() got an unexpected keyword argument 'policy_listener'
<Greenlet at 0x1cceb90: <bound method SocketIOServer.wrap_socket_and_handle of <SocketIOServer at 0x1dc0710 fileno=3 address=0.0.0.0:8080>>(<socket at 0x1dc08d0 fileno=10 sock=127.0.0.1:8080, ('127.0.0.1', 45824))> failed with TypeError

Traceback (most recent call last):
  File "/usr/local/lib/python2.7/dist-packages/gevent/greenlet.py", line 390, in run
    result = self._run(*self.args, **self.kwargs)
  File "/usr/local/lib/python2.7/dist-packages/gevent/server.py", line 159, in wrap_socket_and_handle
    ssl_socket = self.wrap_socket(client_socket, **self.ssl_args)
TypeError: wrap_socket() got an unexpected keyword argument 'policy_listener'
<Greenlet at 0x1cceb90: <bound method SocketIOServer.wrap_socket_and_handle of <SocketIOServer at 0x1dc0710 fileno=3 address=0.0.0.0:8080>>(<socket at 0x1dc08d0 fileno=10 sock=127.0.0.1:8080, ('127.0.0.1', 45826))> failed with TypeError
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1 回答 1

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我想我已经解决了改变这个问题:

if __name__ == '__main__':
    print 'Listening on port http://0.0.0.0:8080 and on port 10843 (flash policy server)'
    SocketIOServer(('0.0.0.0', 8080), Application(),
        resource="socket.io", policy_server=True,
        policy_listener=('0.0.0.0', 10843)).serve_forever(

有了这个:

if __name__ == '__main__':
    print 'Listening on port http://0.0.0.0:8080'
    SocketIOServer(('0.0.0.0', 8080), Application(),
        resource="socket.io").serve_forever(

但我真的不知道为什么。我希望有人能解释一下。谢谢。

于 2013-11-26T08:56:07.487 回答