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Unbekannter Fehler (0x80005000) bei System.DirectoryServices.DirectoryEntry.Bind(Boolean throwIfFail)
bei System.DirectoryServices.DirectoryEntry.Bind()
bei System.DirectoryServices.DirectoryEntry.get_AdsObject()
bei System.DirectoryServices.DirectorySearcher.FindAll(Boolean findMoreThanOne)
bei System.DirectoryServices.DirectorySearcher.FindAll()

这就是返回的内容。我的代码如下所示：

string domain = DNFilterEntry.Key;
DirectoryEntry entry = new DirectoryEntry("LDAP://" + ((domain != "") ? "DC=" + domain : ""));
DirectorySearcher searcher = new DirectorySearcher(entry);
searcher.PropertiesToLoad.Add("displayName");
searcher.PropertiesToLoad.Add("mail");
searcher.Filter = string.Format("(|"+DNfilterEntry.Value+")",filterparams.ToArray());
try
{
    SearchResultCollection users = searcher.FindAll(); // error thrown here
    ...
}
catch (System.Runtime.InteropServices.COMException ex) { Debug.Message(ex.ErrorCode + ex.Message + ex.StackTrace); continue; }

键值对 DNfilterEntry 是"" => "(mail={0})(mail={1})"

和 filterparams 是一个 List 包含两个项目somemail@intra.domain.com和someothermail@intra.domain.com。过滤器正确生成以

(mail=somemail@intra.domain.com)(mail=someothermail@intra.domain.com)

（经 VS 调试器验证；两个邮件地址均有效）

这里的任何人都知道为什么会发生该错误？

编辑：以下用于不同查询的代码可以正常运行：

string Filter="(&";
switch (filterType) {
    case 0: Filter += "(sAMAccountType=805306368)"; break;
    case 1: Filter += "(objectCategory=group)"; break;
    case 2: Filter += "(|(objectCategory=group)(objectCategory=person))"; break;
}
Filter += "(sAMAccountName={0}))";
DirectorySearcher searcher = new DirectorySearcher();
searcher.Filter = string.Format(Filter, username);
SearchResult user = searcher.FindOne();
if (user == null || user.Properties == null || user.Properties[propName] == null || user.Properties[propName][0] == null) return null;
return user.Properties[propName][0].ToString();

propName = "mail", username="someusername", domain="", filterType=0 它返回 someusername 的主要电子邮件地址。

编辑2：

有人能告诉我为什么当我DirectorySearcher searcher = new DirectorySearcher(entry);变成DirectorySearcher searcher = new DirectorySearcher();

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0 回答 0