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我目前正在尝试使用 PrintStream 方法使我的代码生成输出文件。我的教科书建议我在我的主目录中使用这行特定的代码：

    PrintStream output = new PrintStream(new File("results.txt"));

但是，当我输入这行代码时，Java 给了我以下错误：

    Personality.java:17: error: variable output is already defined in method main(String[])
    PrintStream output = new PrintStream(new File("results.txt"));
                ^
    Personality.java:23: error: cannot find symbol
        output.println();
              ^

我的主要方法目前如下所示：

    public class Personality {
public static void main (String[] args)  throws FileNotFoundException   {
    Scanner input = new Scanner(System.in);
    intro();
    Scanner output = asksForFile(input);
    PrintStream output = new PrintStream(new File("results.txt"));
  while(output.hasNextLine()){
        int[] aCounts = new int[4];
        int[] bCounts = new int[4];
        String name = output.nextLine();
        String data = output.nextLine();
        output.println();
        System.out.print(name + ": ");
        int[] percentB = numberOfAnswers(name, data, aCounts, bCounts);
        output.print(Arrays.toString(percentB));
     output.print(" = ");
        output.println(determineType(percentB));    
    }       
}

我从错误中猜测，我不能在一个方法中定义两次输出，但是如果我没有定义我的输出，我的程序怎么知道那个符号是什么？另外，如果我已经在 main 中定义了输出，我还能调用什么来使 PrintStream 工作，同时还保持程序的其余部分运行？

我将 main 中的“输出”变量重命名为扫描仪，但我收到了这个新错误：

    Personality.java:34: error: cannot find symbol
    output.println("This program processes a file of answers to the");
    ^
      symbol:   variable output
  location: class Personality

这是我的整个代码目前的样子：

import java.util.*;
import java.io.*;

public class Personality {
    public static void main (String[] args)  throws FileNotFoundException   {
        Scanner input = new Scanner(System.in);
        intro();
        Scanner scanner = asksForFile(input);
        PrintStream output = new PrintStream(new File("results.txt"));

      while(scanner.hasNextLine()){
            int[] aCounts = new int[4];
            int[] bCounts = new int[4];
            String name = scanner.nextLine();
            String data = scanner.nextLine();
            output.println();
            System.out.print(name + ": ");
            int[] percentB = numberOfAnswers(name, data, aCounts, bCounts);
            output.print(Arrays.toString(percentB));
         output.print(" = ");
            output.println(determineType(percentB));    
        }       
    }

   //Introduces the program
    public static void intro()  {
        output.println("This program processes a file of answers to the");
        output.println("Keirsey Temperament Sorter.  It converts the");
      output.println("various A and B answers for each person into");
      output.println("a sequence of B-percentages and then into a");
        output.println("four-letter personality type.");
        output.println();       
    }

    //Asks for input file
    public static Scanner asksForFile(Scanner input) throws FileNotFoundException   {
        output.print("input file name? ");
        String filename = input.nextLine();
        return new Scanner(new File(filename));

    }

   //This while loop puts counts inside arrays
    public static int[] numberOfAnswers(String name, String data, int[] aCounts, int[] bCounts)  throws FileNotFoundException   {
        data = data.toLowerCase();
        for (int i = 0; i < data.length(); i++) {
            int x = ((i % 7) + 1) / 2;
            if (data.charAt(i) == 'a'){
                aCounts[x]++;
            } else if(data.charAt(i) == 'b'){
                bCounts[x]++;
            }
        }
        return percentB(aCounts, bCounts);
    }

    public static void printOutcome(int[] aCounts, int[] bCounts){
        String[] ratios = new String[4];
        for(int i = 0; i < 4; i++){
            String temp = aCounts[i] + "A-" + bCounts[i] + "B";
            ratios[i] = temp;
        }
        output.println(Arrays.toString(ratios));
    }

    public static int[] percentB(int[] aCounts, int[] bCounts){
        int[] percentB = new int[4];
        for(int i = 0; i < 4; i++){
            double percent = (double) bCounts[i] / (aCounts[i] + bCounts[i]);
            percentB[i] = (int) Math.round(percent * 100);
        }
        return percentB;    
    }

    public static String determineType(int[] percentB){
        String sub50 = "ESTJ";
        String sup50 = "INFP";
        String type = "";
        for(int i = 0; i < 4; i++){
            if(percentB[i] > 50){
                type += sup50.charAt(i);
            } else if(percentB[i] < 50){
                type += sub50.charAt(i);
            } else {
                type += "X";
            }
        }
        return type;
    }

}

4

1 回答 1

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代码中有两个同名的变量，这是不允许的。更改这些变量名称之一并重构代码：

Scanner output = asksForFile(input);
PrintStream output = new PrintStream(new File("results.txt"));

重构版本

public class Personality {
    public static void main (String[] args)  throws FileNotFoundException   {
        Scanner input = new Scanner(System.in);
        intro();
        Scanner scanner = asksForFile(input);
        PrintStream output = new PrintStream(new File("results.txt"));

        while(scanner.hasNextLine()){
            int[] aCounts = new int[4];
            int[] bCounts = new int[4];
            String name = scanner.nextLine();
            String data = scanner.nextLine();
            output.println();
            System.out.print(name + ": ");
            int[] percentB = numberOfAnswers(name, data, aCounts, bCounts);
            output.print(Arrays.toString(percentB));
            output.print(" = ");
            output.println(determineType(percentB));    
        }       
    }
}

注意此代码段中有几种方法未提供源代码。鉴于这些未知因素，此版本可能需要额外的重构。

于 2013-11-21T01:30:00.757 回答