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当用户对他/她已经评论过的节点发表评论时，我想在我的评论表单中隐藏 Fivestar 评级字段（称为“field_stars”）。我在我的网站上有一个名为Commented的标志，还有一个规则，当有人评论它时代表评论员标记一个节点（效果很好）。我试图根据我在这里找到的信息来解决我的问题：

function hiderating_form_alter(&$form, &$form_state, $form_id) {
  global $user;
  $flag = flag_get_flag('commented') or die('no "commented" flag defined');
  if ($form_id == "comment_node_stuff_form") {
   if ($flag->is_flagged($form['#node']->uid, $user->uid)) { 
      unset($form['field_stars']);
    }
  }
}

不幸的是，它并没有改变任何东西（我也没有收到任何错误）。我做错了什么？

在使用@jerdiggity 的代码进行调试后，我得到：

DEBUG: form id "comment_node_stuff_form" found. Debugging...
DEBUG: The code $flag->is_flagged($form["#node"]->uid, $user->uid) is returning FALSE.

（当然我也明白了DEBUG: final form structure:，但在这里粘贴太长了）。我不明白为什么无法识别标记，因为它存储在数据库中......

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1 回答 1

1

尝试添加这些调试值以找到问题的根源（当然不是在实时服务器上......仅在开发环境中）：

function hiderating_form_alter(&$form, &$form_state, $form_id) {
  global $user;
  if ($form_id == "comment_node_stuff_form") {
    // I'm not sure why the examples make use of "die" because that will stop the entire
    // site from continuing any further.
    $flag = flag_get_flag('commented');

    // ** Begin debug ** //
    // Notify us that we've at least got the right form.
    drupal_set_message(t('DEBUG: form id "comment_node_stuff_form" found. Debugging...'), 'warning');
    // Warn us if $flag is giving us issues
    if (!$flag) {
      drupal_set_message(t('DEBUG: No "commented" flag defined.'), 'warning');
    }
    // Check form components
    if (!isset($form['#node']) || !$form['#node']) {
      drupal_set_message(t('DEBUG: Something is wrong with or missing from $form["#node"]'), 'warning'); 
    }
    // Check more form components
    if (!isset($form['#node']->uid)) {
      drupal_set_message(t('DEBUG: $form["#node"]->uid is not set.'), 'warning'); 
    }
    // Again
    if (!isset($form['field_stars']) || empty($form['field_stars'])) {
      drupal_set_message(t('DEBUG: <em>$form["field_stars"]</em> is not set or is empty/false.'), 'warning'); 
    }
    // Check flag stuff
    if (!$flag->is_flagged($form['#node']->nid, $user->uid)) {
      drupal_set_message(t('DEBUG: The code <em>$flag->is_flagged($form["#node"]->nid, $user->uid)</em> is returning FALSE.'), 'warning'); 
    }
    // Again...
    if (!$flag->is_flagged($form['#node']->uid, $user->uid)) {
      drupal_set_message(t('DEBUG: The code <em>$flag->is_flagged($form["#node"]->uid, $user->uid)</em> is returning FALSE.'), 'warning'); 
    }
    // ** End debug ** //

    // Changing this to nid instead of uid
    if ($flag->is_flagged($form['#node']->nid, $user->uid)) { 
      unset($form['field_stars']);
    }
    // One more debug item:
    drupal_set_message('DEBUG: final form structure:<br/><pre>' . check_plain(print_r($form, 1)) . '</pre>', 'warning');
  }
}
于 2013-11-19T22:54:20.480 回答