jquery - 使用 jquery 扩展来避免编辑 jquery 标准库

Question

我想为 jquery $.ajax 调用添加一些功能。具体来说，我想捕获 http 错误 403。我不想编辑 jquery JS 本身。我开始查看 .extend 但对这些示例感到有些困惑。

我可以使用 $.extend $.ajax() 来捕获 403 吗？

TIA 僵尸杀手。

Answer 1

你看过jQuery.ajaxSetup选项吗？还是在jQuery.ajaxError？

无论哪种方式，都不要编辑 jQuery 源代码。

Answer 2

Extend doesn't work like that. You might be better served by something like this:

jQuery.fn.myCustomAjax = function() {
    // custom code here
    jQuery.ajax(); // etc
};

The #1 major benefit of this is that it won't stuff with any external code (plugins) and will be much easier to work with when you upgrade jQuery.

Answer 3

Thanks Guys. The suggested solution wont work becuase I need to trap for specific http result codes and then "do something special" via javascript.

so I have added 5 lines of code to jquery core library (I know dont flame me). To solve this problem in the core I suggest the following parameter would be added to jquery core libs (new parameter is responseHandlers)

$.ajax(
     responseHandlers: {
          "403":function() { http403(); } ,
          "500":function() { http500(); }
     }

global scoped:

function http403()
{
}

function http500()
{
}