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我编写了一个 Django（遗憾的是 1.3 版）管理命令来使用 Selenium 连接到 BrowserStack，并将用于运行集成测试。（我不得不编写一个自定义管理命令来解决我们在这个站点中使用 AskBot 的事实，它以一些有趣的方式弄乱了 Django 测试框架；否则我会简单地使用测试框架。）

脚本的要点在这里https://gist.github.com/cellofellow/7491221。这是早期脚本的一个端口，它直接运行 unittest 而没有任何 Django 上下文。

发生的情况是，当运行时，我会得到这样的回溯：

./manage.py browserstack signup
Browser: IE
Browser Version: 10.0
Operating System: Windows
OS Version: 7

E
======================================================================
ERROR: runTest (apps.common.management.commands.browserstack.SignUpBasic)
----------------------------------------------------------------------
Traceback (most recent call last):
  File "/home/jgardner/izeni/doterra_pro/apps/common/management/commands/browserstack.py", line 46, in setUp
    desired_capabilities=self.caps)
  File "/home/jgardner/.virtualenvs/doterra_pro/local/lib/python2.7/site-packages/selenium/webdriver/remote/webdriver.py", line 71, in __init__
    self.start_session(desired_capabilities, browser_profile)
  File "/home/jgardner/.virtualenvs/doterra_pro/local/lib/python2.7/site-packages/selenium/webdriver/remote/webdriver.py", line 113, in start_session
    'desiredCapabilities': desired_capabilities,
  File "/home/jgardner/.virtualenvs/doterra_pro/local/lib/python2.7/site-packages/selenium/webdriver/remote/webdriver.py", line 162, in execute
    response = self.command_executor.execute(driver_command, params)
  File "/home/jgardner/.virtualenvs/doterra_pro/local/lib/python2.7/site-packages/selenium/webdriver/remote/remote_connection.py", line 355, in execute
    return self._request(url, method=command_info[0], data=data)
  File "/home/jgardner/.virtualenvs/doterra_pro/local/lib/python2.7/site-packages/selenium/webdriver/remote/remote_connection.py", line 402, in _request
    response = opener.open(request)
  File "/usr/lib/python2.7/urllib2.py", line 410, in open
    response = meth(req, response)
  File "/usr/lib/python2.7/urllib2.py", line 523, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib/python2.7/urllib2.py", line 442, in error
    result = self._call_chain(*args)
  File "/usr/lib/python2.7/urllib2.py", line 382, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 897, in http_error_401
    url, req, headers)
  File "/usr/lib/python2.7/urllib2.py", line 872, in http_error_auth_reqed
    response = self.retry_http_basic_auth(host, req, realm)
  File "/usr/lib/python2.7/urllib2.py", line 885, in retry_http_basic_auth
    return self.parent.open(req, timeout=req.timeout)
  File "/usr/lib/python2.7/urllib2.py", line 404, in open
    response = self._open(req, data)
  File "/usr/lib/python2.7/urllib2.py", line 422, in _open
    '_open', req)
  File "/usr/lib/python2.7/urllib2.py", line 382, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 1214, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib/python2.7/urllib2.py", line 1187, in do_open
    r = h.getresponse(buffering=True)
  File "/usr/lib/python2.7/httplib.py", line 1045, in getresponse
    response.begin()
  File "/usr/lib/python2.7/httplib.py", line 409, in begin
    version, status, reason = self._read_status()
  File "/usr/lib/python2.7/httplib.py", line 365, in _read_status
    line = self.fp.readline(_MAXLINE + 1)
  File "/usr/lib/python2.7/socket.py", line 476, in readline
    data = self._sock.recv(self._rbufsize)
timeout: timed out

----------------------------------------------------------------------
Ran 1 test in 5.201s

FAILED (errors=1)

在 BrowserStack 中启动了一个实例，但是因为接下来发生的任何事情都无法连接，它只是运行了一分钟左右然后退出。

移植它的脚本没有这个问题。可能是什么原因造成的？

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1 回答 1

2

原来我只需要设置这个代码库socket.setdefaulttimeout(60)中有几十个调用socket.setdefaulttimeout，包括依赖项和我们自己的代码，所以谁知道它实际上设置了什么。

于 2013-11-16T04:02:49.200 回答