1

文本文件中的一些数据:

date,p
2013-11-14,0.001
2013-11-13,-0.005
2013-11-12,0.001

library(PerformanceAnalytics)
stuff<-read.csv("C:stuffexample.txt")
str(stuff)

'data.frame':   3 obs. of  2 variables:
 $ date: Factor w/ 3 levels "2013-11-12","2013-11-13",..: 3 2 1
 $ p   : num  0.001 -0.005 0.001

想要对数据使用性能分析:

AverageDrawdown(stuff)

Error in checkData(R) : 
  The data cannot be converted into a time series.  If you are trying to pass in names from a data object with one column, you should use the form 'data[rows, columns, drop = FALSE]'.  Rownames should have standard date formats, such as '1985-03-15'. 

table.Drawdowns(box)

Error in checkData(R[, 1, drop = FALSE]) : 
  The data cannot be converted into a time series.  If you are trying to pass in names from a data object with one column, you should use the form 'data[rows, columns, drop = FALSE]'.  Rownames should have standard date formats, such as '1985-03-15'. 

如何修复错误?

4

1 回答 1

2

您需要遵循错误中给出的建议。您应该在 data.frame 中有日期的行名和只有数据:

row.names(stuff) <- levels(stuff$date)[stuff$date]
stuff2 <- stuff[, 'p', drop=FALSE]

AverageDrawdown(stuff2)

这是未经测试的,因为您没有提供可重现的示例...

于 2013-11-15T18:51:40.670 回答