sql - 如何从数量的总和中找到最大值

Question

示例表订单

+---------+----------+
| 订单号 | 数量 |
+---------+----------+
| 10248 | 11 |
| 10248 | 42 |
| 10248 | 72 |
| 10249 | 14 |
| 10249 | 51 |
| 10250 | 41 |
| 10250 | 51 |
+---------+----------+

我的问题是。如何找到每个orderid的数量总和并找到订单的最高数量

<select orderid , SUM(quantity) As TotalQty  from order group by orderid

结果

+--------+------------+
|订单号 | 总数量 |
+--------+------------+
| 10248 | 125 |
| 10249 | 65 |
| 10250 | 92 |
+--------+------------+

从上面的结果中，我需要显示总数最高的 orderid。

最终结果必须是

+--------+----------+
|订单号 | 总数量 |
+--------+----------+
| 10245 | 125 |
+--------+----------+

我在一个查询中需要这个

Answer 1

在 MySQL 中使用

select orderid, SUM(quantity) As TotalQty
from order 
group by orderid
order by TotalQty desc
limit 1

在 MSSQL 中

select top 1 orderid, SUM(quantity) As TotalQty
from order 
group by orderid
order by SUM(quantity) desc

在甲骨文中

select orderid, SUM(quantity) As TotalQty
from order 
group by orderid
order by SUM(quantity) desc
where ROWNUM <= 1

Answer 2

在 SQL-Server 的情况下，您可以使用以下OVER子句：

SELECT TOP 1 orderid, SUM(Quantity)OVER(PARTITION BY orderid)AS TotalQTY
FROM dbo.Orders
ORDER BY TotalQTY DESC

Demo

您可以包括所有列，即使它们不是聚合的或不属于GROUP BY.

Answer 3

甲骨文：

select * from (
select orderid, SUM(quantity) As TotalQty
from order
group by orderid
order by TotalQty desc) where rownum =1;

Answer 4

mysql:

select orderid, SUM(quantity) As TotalQty
from order 
group by orderid
order by TotalQty desc
limit 1

Answer 5

with cte IN SQL SERVER

;with cte as
(
 select top 1 orderid,sum(TotalQTY) as x from table group by id
 )

 select * from cte
 OPTION (MAXRECURSION 1);