14

我需要获取给定目录中的所有 .config 文件,并且在每个文件中我需要搜索特定字符串并根据文件替换为另一个。

例如,如果我在给定目录中有 3 个文件:

 for  my_foo.config - string to search "fooCommon >" replace with "~ /fooCommon[\/ >"
 for  my_bar.config - string to search "barCommon >" replace with "~ /barCommon[\/ >"
 for  my_file.config - string to search "someCommon >" replace with "~ /someCommon[\/ >"

请让我知道如何在 Perl 中做到这一点?

下面是我在 shell 脚本中尝试的代码:

OLD="\/fooCommon >"
NEW="~ \"\/fooCommon[^\/]*\" >"
DPATH="/myhome/aru/conf/host*.conf"
BPATH="/myhome/aru/conf/bakup"
TFILE="/myhome/aru/out.tmp.$$"
[ ! -d $BPATH ] && mkdir -p $BPATH || :
for f in $DPATH
do
  if [ -f $f -a -r $f ]; then
   /bin/cp -f $f $BPATH
   echo sed \"s\/$OLD\/$NEW\/g\"
   sed "s/$OLD/$NEW/g" "$f" > $TFILE && mv $TFILE "$f"
  else
   echo "Error: Cannot read $f"

fi
done
/bin/rm $TFILE
4

7 回答 7

34

如果你在类 Unix 平台上,你可以在命令行上使用 Perl 来完成;无需编写脚本。

perl -i -p -e 's/old/new/g;' *.config

为了更安全,您可能需要使用带有备份选项的命令。

perl -i.bak  -p -e 's/old/new/g;' *.config
于 2013-11-15T08:39:50.877 回答
11

这里的 Perl 只是为了修改文件......我不明白为什么要在 perl 中完整地编写它,如果你可以像这样更简单地做到这一点:

find . -maxdepth 1 -type f -name '*.conf' | \
    xargs perl -i.bak -pe 's/localhost/example.com/;'
于 2013-11-15T08:37:31.743 回答
3

如果您真的只需要使用 perl 来执行此操作,我不建议这样做,因为已经发布了出色且更简单的答案,这里是:

#!/usr/bin/perl

# take the directory to be processed from first command line argument
opendir($dh, $ARGV[0]);
# take only relevant files ie. "*.config"
@cfgs = grep { /\.config$/ } readdir($dh);
# loop through files
foreach(@cfgs) {
  # generate source string from the filename
  ($s) = ($_ =~ /.*_(\w+)\.config.*/);
  $s = "${s}Common";
  # generate replacement string from the filename
  $r = "~ /${s}[/ >";
  # move original file to a backup
  rename("${ARGV[0]}${_}", "${ARGV[0]}${_}.bak");
  # open backup file for reading
  open(I, "< ${ARGV[0]}${_}.bak");
  # open a new file, with original name for writing
  open(O, "> ${ARGV[0]}${_}");
  # go through the file, replacing strings
  while(<I>) { $_ =~ s/$s/$r/g; print O $_; }
  # close files
  close(I);
  close(O);
}

# end of file.

请注意,使用简单的查找和/或外壳通配符执行此操作要简单得多。但是,请将此作为一个关于如何使用 perl 处理文件的小教程。

于 2013-11-15T08:42:39.070 回答
1

虽然它可以从命令行完成,但有时您只需要一个易于使用的脚本,它可以提供更有用的输出。考虑到这一点,这里有一个 perl 解决方案,对于遇到此问题的任何人都具有友好的输出。

#!/usr/bin/env perl5.8.3

# subst [-v] [-f] "re/string to find" "string to replace" -- list of files
#  optional -v flag shows each line with replacement, must be 1st arg to script
#  optional -f flag says to disable regexp functionality and make the strings match exactly
#  replacement string may include back references ($1, $2, etc) to items in "string to find" if they are surrounded by grouping parenthesis

use strict;
use warnings;
use List::Util;
use IO::File;
use Fcntl;
use Getopt::Long qw(GetOptions);

my $verbose = 0;
my $fixed   = 0;

GetOptions("v" => \$verbose,
           "f" => \$fixed);

my $find    = shift @ARGV;
my $replace = shift @ARGV;

die "Error: missing 1st arg, string to find\n"         if not defined $find;
die "Error: missing 2nd arg, string to replace with\n" if not defined $replace;
die "No files were specified\n"                        if @ARGV == 0;

# open a temp file for writing changes to
my $TEMP = IO::File->new_tmpfile;
if (not defined $TEMP)
{
    print STDERR "ERROR: failed to create temp file: $!\n";
    exit 1;
}

# Fix max file name width for printing
my $fwidth = List::Util::max map { length $_ } @ARGV;

# Process each file
my $unchanged = 0;
my $changed   = 0;
foreach my $file (@ARGV)
{
    if (open(my $FILE, '<', $file))
    {
        # Reset temp file
        seek $TEMP, 0, SEEK_SET or die "ERROR: seek in temp file failed: $!";
        truncate $TEMP, 0       or die "ERROR: truncate of temp file failed: $!";

        # go through the file, replacing strings
        my $changes = 0;
        while(defined(my $line = <$FILE>))
        {
            if ($line =~ m/$find/g)
            {
                print "-" . $line if $verbose;
                print "\n" if $verbose and $line !~ m/\n$/;

                if ($fixed)
                {
                    my $index = index($line, $find);
                    substr($line, $index, length($find)) = $replace;
                }
                else
                {
                    $line =~ s/$find/replacebackrefs($replace)/eg;
                }

                $changes++;
                print "+" . $line if $verbose;
                print "\n" if $verbose and $line !~ m/\n$/;
            }

            print $TEMP $line;
        }
        close $FILE;

        if ($changes == 0)
        {
            $unchanged++;
            unlink("/tmp/subst$$");
            next;
        }

        # Move new contents into old file
        $changed++;
        printf "%*s - %3d changes\n", -$fwidth, $file, $changes;

        seek $TEMP, 0, SEEK_SET or die "ERROR: rewind of temp file failed: $!";
        open $FILE, '>', $file or die "ERROR: failed to re-write $file: $!\n";
        while (<$TEMP>) { print $FILE $_ }
        close $FILE;

        print "\n" if $verbose;
    }
    else
    {
        print STDERR "Error opening $file: $!\n";
    }
}

close $TEMP;

print "\n";
print "$changed files changed, $unchanged files unchanged\n";

exit 0;

sub replacebackrefs
{
    # 1st/only argument is the text matched
    my $matchedtext = shift @_;

    my @backref;
    # @- is a dynamic variable that holds the offsets of submatches in
    # the currently active dynamic scope (i.e. within each regexp
    # match), corresponding to grouping parentheses. We use the count
    # of entrees in @- to determine how many matches there were and
    # store them into an array. Note that @- index [0] is not
    # interesting to us because it has a special meaning (see man
    # perlvar for @-)\, and that backrefs start with $1 not $0.
    # We cannot do the actual replacement within this loop.
    do
    {
        no strict 'refs'; # turn of warnings of dynamic variables
        foreach my $matchnum (1 .. $#-)
        {
            $backref[$matchnum] = ${$matchnum}; # i.e. $1 or $2 ...
        }
    } while(0);

    # now actually replace each back reference in the matched text
    # with the saved submatches.
    $matchedtext =~ s/\$(\d+)/$backref[$1]/g;

    # return a scalar string to actually use as the replacement text,
    # with all the backreferences in the matched text replaced with
    # their submatch text.
    return $matchedtext;
}
于 2014-12-22T23:19:43.297 回答
0

也许以下内容会有所帮助:

use strict;
use warnings;

my %replacements =
  map { chomp; my @x = split /\|/; $x[0] => [ $x[1], $x[2] ] } <DATA>;

local $^I = '.bak';

for my $file (<*.config>) {
    push @ARGV, $file;

    while (<>) {
        s/\b\Q$replacements{$file}[0]/$replacements{$file}[1]/g;
        print;
    }
}

__DATA__
my_foo.config|fooCommon >|~ /fooCommon[/ >
my_bar.config|barCommon >|~ /barCommon[/ >
my_file.config|someCommon >|~ /someCommon[/ >

数组散列 (HoA) 是通过split使用|-delimited DATA 行构建的,其中键是文件名,值是对匿名数组的引用,该数组的两个元素用于替换文件。该local $^I = '.bak'符号创建原始文件的备份。

您可能需要调整替换。例如,使用\bin在替换中观察到单词边界s/\b\Q$replacements{$file}[0]/$replacements{$file}[1]/g;。您可能需要也可能不需要(或想要)这个。

我建议先在一个“临时”文件上尝试它,以确保在完全实施之前获得所需的结果——即使原始文件已备份。

于 2013-11-15T19:54:57.307 回答
0

你的脚本是一个很好的尝试。

它包含一些冗余:

  • 没用cp $f
  • $TFILE也没用(直接将sed输出写入目标文件)

您可以从没有目录路径的值构造$NEW和目标文件名$f,您可以通过以下方式获取:

bf=`basename "$f"`
于 2014-12-23T08:08:10.897 回答
0

对于那些想要递归替换目录及其子目录的所有文本文件中的字符串的人来说,这个单行可能有用:

grep -r OLD_STRING * | cut -d':' -f1 | uniq | xargs perl -i -pe 's/OLD_STRING/NEW_STRING/g;'
于 2021-04-30T07:59:13.933 回答