我刚刚进入 PHP、Javascript 和 HTML 的世界,并希望社区提供有关以下代码的一些帮助。基本上,我想将 PHP 从 ODBC_connection 中提取的变量传递到文本框中。第 1-3 行是让我测试让框更新它所做的,但 PHP 回显的任何内容都不会运行。我对此完全陌生,所以我意识到我一定遗漏了一些微不足道的东西。
我欢迎任何关于我可以做些什么来解决这个问题或我可以做得更好的建议或意见。谢谢你。
<script type='text/javascript'>
document.getElementById('modeltxt').value = "test2";
</script>
<?php
echo "<script type='text/javascript'>";
echo "document.getElementById('modeltxt').value =\"TEST3\";";
echo "document.getElementById('customertxt').value = $customer;";
echo "document.getElementById('endusertxt').value = $enduser;";
echo "document.getElementById(dongletxt').value = $dongle;";
echo "document.getElementById('shipdatetxt').value = $shipdate;";
echo "document.getElementById('chasistypetxt').value = $chasistype;";
echo "document.getElementById('chasisnumbertxt').value = $chasisnumber;";
echo "document.getElementById('opsystxt').value = $opsys;";
echo "document.getElementById('dvd1txt').value = $dvd1;";
echo "document.getElementById('dvd2txt').value = $dvd2;";
echo "document.getElementById('storagetxt').value = $storage;";
echo "document.getElementById('nodrivetxt').value = $nodrive;";
echo "document.getElementById('drivesizetxt').value = $drivesize;";
echo "document.getElementById('interface1txt').value = $interface1;";
echo "document.getElementById('interface2txt').value = $interface2;";
echo "document.getElementById('interface3txt').value = $interface3;";
echo "document.getElementById('interface4txt').value = $interface4;";
echo "document.getElementById('interface5txt').value = $interface5;";
echo "document.getElementById('interface6txt').value = $interface6;";
echo "document.getElementById('commentstxt').value = $comments;";
echo "document.getElementById('warrantyexptxt').value = $warrantyexp;";
echo "document.getElementById('extendedwarrantytxt').value = $extwarexp;";
echo "document.getElementById('onsitetxt').value = $onsite;";
echo "document.getElementById('sqlversiontxt').value = $sqlversion;";
echo "<\script>";