所以我有一个我构建的堆栈,我有一个机器来评估像 (9 + 0) 这样的表达式,它们可以更复杂。我在命令行中运行它,然后当我输入示例( 9 + 5 )时,程序就停在那里。我可以换行,但表达式不计算。所以我的问题是我错过了什么。我确信有些东西我没有正确理解,我在想我缺少关于 Scanner 或 Java 中的数组的一些东西。
也许我昨晚在想我应该用 ArrayList 替换数组。这有意义吗?
这是固定容量堆栈
public class FCStack<Item> {
private Item[] a;
private int top; // pointer to top of Stack
private int capacity; // size of the Stack+1
public FCStack(int cap){
capacity = cap;
a = (Item[]) new Object[capacity];
top = 0;
}
public void push(Item i){ //will only push an Item to the Stack if there is room.
if (!isFull()) {
a[top++] = i;
}
}
public Item pop(){ //will only pop an Item from the stack if there is something to pop.
if (!isEmpty()) {
--top;
}
return a[top];
}
public boolean isFull(){ //returns true if is full
return top == capacity;
}
public boolean isEmpty(){ //returns true if is empty
return top == 0;
}
public int size(){ //returns the current size of the stack+1 or the array index
return top;
}
}
这是两个堆栈评估器
import java.io.*;
import java.util.Scanner;
public class TwoStackMaths {
public static void main (String[] args) {
FCStack<String> ops = new FCStack<String>(10);
FCStack<Double> vals = new FCStack<Double>(10);
Scanner console = new Scanner(System.in);
while(console.hasNext()) {
String str = console.next();
if (str.equals("("))
;
else if (str.equals("+")) {
ops.push(str);
}
else if (str.equals("-")) {
ops.push(str);
}
else if (str.equals("*")) {
ops.push(str);
}
else if (str.equals("/")) {
ops.push(str);
}
else if (str.equals("^")) {
ops.push(str);
}
else if (str.equals(")")) {
String op = ops.pop();
double v = vals.pop();
if (op.equals("+")) {
v = vals.pop() + v;
}
else if (op.equals("-")) {
v = vals.pop() - v;
}
else if (op.equals("*")) {
v = vals.pop() * v;
}
else if (op.equals("/")) {
v = vals.pop() / v;
}
else if (op.equals("^")) {
v = Math.pow(v, vals.pop());
}
vals.push(v);
}
else {
vals.push(Double.parseDouble(str));
}
}
//console.close();
System.out.println(vals.pop());
}
}