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我有这些模型：

class User < ActiveRecord::Base
  has_many :managements, class_name: 'Management', foreign_key: :manager_id
  has_many :primary_locations, -> { where managements:
    { manager_role: "primary" } }, through: :managements,
    source: :manageable, source_type: 'Location'
  has_many :secondary_locations, -> { where managements:
    { manager_role: "secondary" } }, through: :managements,
    source: :manageable, source_type: 'Location'
  has_many :primary_departments, -> { where managements:
    { manager_role: "primary" } }, through: :managements,
    source: :manageable, source_type: 'Department'
  has_many :secondary_departments, -> { where managements:
    { manager_role: "secondary" } }, through: :managements,
    source: :manageable, source_type: 'Department'
end

用户可以管理多个部门和地点，并且可以是每个部门的主要或次要经理：

class Management < ActiveRecord::Base
  belongs_to :manager, class_name: 'User', foreign_key: :manager_id
  belongs_to :manageable, polymorphic: true
end

class Location < ActiveRecord::Base
  has_many :managements, class_name: "Management", foreign_key: :manageable_id,
    as: :manageable
  has_many :primary_managers, -> { where management:
    { manager_role: "primary" } }, through: :managements, source: :manager
  has_many :secondary_managers, -> { where management:
    {manager_role: "secondary"} }, through: :managements, source: :manager
end

class Department < ActiveRecord::Base
  has_many :managements, class_name: "Management", foreign_key: :manageable_id,
    as: :manageable
  has_many :primary_managers, -> { where management:
    { manager_role: "primary" } }, through: :managements, source: :manager
  has_many :secondary_managers, -> { where management:
    {manager_role: "secondary"} }, through: :managements, source: :manager
end

当我调用时，以下关联会产生错误user.primary_departments：

SELECT "departments".* FROM "departments" INNER JOIN "managements" ON
  "departments"."id" = "managements"."manageable_id" WHERE
  "managements"."manager_role" = 'primary' AND "managements"."manager_id" = $1
   AND "departments"."manageable_type" = 'Department'  [["manager_id", 1]]
PG::UndefinedColumn: ERROR:  column department.manageable_type does not exist

location.primary_managers协会工作。所以它似乎几乎可以工作，除了多态类型指向错误的表。我如何指定在桌子manageable_type上找到的？management

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1 回答 1

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我最终将其添加到User课程中：

%w(department location).each do |type|
  %w(primary secondary).each do |role|
    define_method("#{role}_managed_#{type}s") do
      klass = type.capitalize.constantize
      klass.joins("#{role}_managers".to_sym).where('manager_id = ?', id)
    end
  end
end

它增加了 4 个方法：primary_managed_departments、secondary_managed_departments、primary_managed_locations和secondary_managed_locations。这是一种适合我们需求的解决方法，但我可能还缺少其他东西。我将这个答案主要留给@janko-m，因为我无法将格式化的代码放在评论中，所以请随时用更好的解决方案来回答。

于 2013-11-19T02:19:10.767 回答