7

据我所知，如果我声明了一本字典，我可以调用 myDict.Clear() 来重用。

现在，如果我将 sb 声明为 StingBuilder obj。

StringBuilder sb = new StringBuilder();

如何重用某人？谢谢你。

实际上，我需要为 mainDict 打印所有可能的条件。

像这样的 sb 表达式之一（包含在下面的代码中）

sb.AppendFormat("{0}/{1}/{2}/{3}, {4}", pair1.Key, pair2.Key, pair3.Key, pair4.Key, pair4.Value);
Console.WriteLine(sb.ToString());

如果我声明了很多 StringBuilder obj，我仍然无法检测到有多少 obj 对我来说足够了。实际上 mainDict 非常复杂。上面的代码只是一个练习。谢谢。

代码于 1 月 4 日更新。

using System;
using System.Collections;
using System.Collections.Generic;
using System.Text;


class test
{
    private static Dictionary<string, object> mainDict = new Dictionary<string, object>();

    public static void Main()
    {
        Dictionary<string, object> aSubDict = new Dictionary<string,object>();
        Dictionary<string, object> aSub1Dict = new Dictionary<string, object>();
        Dictionary<string, object> aSub2Dict = new Dictionary<string, object>();
        Dictionary<string, object> aSub3Dict = new Dictionary<string, object>();
        Dictionary<string, object> aSub4Dict = new Dictionary<string, object>();

        mainDict.Add("ADKey", aSubDict);
        mainDict.Add("ASKey", "AValue");
        aSubDict.Add("BDKey", aSub1Dict);
        aSubDict.Add("BSKey", "BValue");
        aSub1Dict.Add("CDKey", aSub2Dict);
        aSub1Dict.Add("CSKey", "CValue");
        aSub2Dict.Add("DDKey",aSub3Dict);
        aSub2Dict.Add("DSKey", "DValue");
        aSub3Dict.Add("EDKey", aSub4Dict);
        aSub3Dict.Add("ESKey", "EValue");
        aSub4Dict.Add("FKey", "FValue");


        StringBuilder sb;

        foreach (KeyValuePair<string, object> pair1 in mainDict)
            // watch out for NullReferenceException
            if (!ReferenceEquals(null, mainDict[pair1.Key]) && (mainDict[pair1.Key] is string))
            {
                Console.WriteLine("Key = {0}, Value = {1}", pair1.Key, pair1.Value);
                sb = new StringBuilder();
                sb.AppendFormat("{0}, {1}", pair1.Key, pair1.Value);
                Console.WriteLine(sb.ToString());
            }
            // IDictionary is not the one from the Generics namespace, it is the one from the System.Collections namespace
            else if (!ReferenceEquals(null, mainDict[pair1.Key]) && (mainDict[pair1.Key] is Dictionary<string, object>))
            {
                foreach (KeyValuePair<string, object> pair2 in (Dictionary<string, object>)pair1.Value)
                    if (!ReferenceEquals(null, ((Dictionary<string, object>)pair1.Value)[pair2.Key]) && (((Dictionary<string, object>)pair1.Value)[pair2.Key] is string))
                    {
                        Console.WriteLine("SubKey = {0}, Value = {1}", pair2.Key, pair2.Value);
                        sb = new StringBuilder();
                        sb.AppendFormat("{0}/{1}, {2}", pair1.Key, pair2.Key, pair2.Value);
                        Console.WriteLine(sb.ToString());
                    }
                    else if (!ReferenceEquals(null, ((Dictionary<string, object>)pair1.Value)[pair2.Key]) && (((Dictionary<string, object>)pair1.Value)[pair2.Key] is Dictionary<string, object>))
                    {
                        foreach (KeyValuePair<string, object> pair3 in (Dictionary<string, object>)pair2.Value)
                            if (!ReferenceEquals(null, ((Dictionary<string, object>)pair2.Value)[pair3.Key]) && (((Dictionary<string, object>)pair2.Value)[pair3.Key] is string))
                            {
                                Console.WriteLine("SubKey = {0}, Value = {1}", pair3.Key, pair3.Value);
                                sb = new StringBuilder();
                                sb.AppendFormat("{0}/{1}/{2}, {3}", pair1.Key, pair2.Key, pair3.Key, pair3.Value);
                                Console.WriteLine(sb.ToString());
                            }
                            else if (!ReferenceEquals(null, ((Dictionary<string, object>)pair2.Value)[pair3.Key]) && (((Dictionary<string, object>)pair2.Value)[pair3.Key] is Dictionary<string, object>))
                            {
                                foreach (KeyValuePair<string, object> pair4 in (Dictionary<string, object>)pair3.Value)
                                    if (!ReferenceEquals(null, ((Dictionary<string, object>)pair3.Value)[pair4.Key]) && (((Dictionary<string, object>)pair3.Value)[pair4.Key] is string))
                                    {
                                        Console.WriteLine("SubKey = {0}, Value = {1}", pair4.Key, pair4.Value);
                                        sb = new StringBuilder();
                                        sb.AppendFormat("{0}/{1}/{2}/{3}, {4}", pair1.Key, pair2.Key, pair3.Key, pair4.Key, pair4.Value);
                                        Console.WriteLine(sb.ToString());
                                    }
                                    else if (!ReferenceEquals(null, ((Dictionary<string, object>)pair3.Value)[pair4.Key]) && (((Dictionary<string, object>)pair3.Value)[pair4.Key] is Dictionary<string, object>))
                                    {
                                        foreach (KeyValuePair<string, object> pair5 in (Dictionary<string, object>)pair4.Value)
                                            if (!ReferenceEquals(null, ((Dictionary<string, object>)pair4.Value)[pair5.Key]) && (((Dictionary<string, object>)pair4.Value)[pair5.Key] is string))
                                            {
                                                Console.WriteLine("SubKey = {0}, Value = {1}", pair5.Key, pair5.Value);
                                                sb = new StringBuilder();
                                                sb.AppendFormat("{0}/{1}/{2}/{3}/{4}, {5}", pair1.Key, pair2.Key, pair3.Key, pair4.Key, pair5.Key, pair5.Value);
                                                Console.WriteLine(sb.ToString());
                                            }
                                            else if (!ReferenceEquals(null, ((Dictionary<string, object>)pair4.Value)[pair5.Key]) && (((Dictionary<string, object>)pair4.Value)[pair5.Key] is Dictionary<string, object>))
                                            {
                                                foreach (KeyValuePair<string, object> pair6 in (Dictionary<string, object>)pair5.Value)
                                                    if (!ReferenceEquals(null, ((Dictionary<string, object>)pair5.Value)[pair6.Key]) && (((Dictionary<string, object>)pair5.Value)[pair6.Key] is string))
                                                    {
                                                        Console.WriteLine("SubKey = {0}, Value = {1}", pair6.Key, pair6.Value);
                                                        sb = new StringBuilder();
                                                        sb.AppendFormat("{0}/{1}/{2}/{3}/{4}/{5}, {6}", pair1.Key, pair2.Key, pair3.Key, pair4.Key, pair5.Key, pair6.Key, pair6.Value);
                                                        Console.WriteLine(sb.ToString());
                                                    }
                                                    else if (!ReferenceEquals(null, ((Dictionary<string, object>)pair5.Value)[pair6.Key]) && (((Dictionary<string, object>)pair5.Value)[pair6.Key] is Dictionary<string, object>))
                                                    {
                                                        Console.WriteLine("sub Dict Found");
                                                    }
                                            }
                                    }
                            }
                    }
            }         
    }

}

像这样输出

SubKey = FKey, Value = FValue
ADKey/BDKey/CDKey/DDKey/EDKey/FKey, FValue
SubKey = ESKey, Value = EValue
ADKey/BDKey/CDKey/DDKey/ESKey, EValue
SubKey = DSKey, Value = DValue
ADKey/BDKey/CDKey/DSKey, DValue
SubKey = CSKey, Value = CValue
ADKey/BDKey/CSKey, CValue
SubKey = BSKey, Value = BValue
ADKey/BSKey, BValue
Key = ASKey, Value = AValue
ASKey, AValue
4

2 回答 2

22

您可以将 设置Length为 0。在 .NET 4.0 中也有一个Clear()方法。作为Clear状态的文档：

Clear 是一种方便的方法，相当于将当前实例的 Length 属性设置为 0（零）。

所以这没什么大不了的:)

我个人会避免这样做，除非你真的需要——我通常只是创建一个新的StringBuilder. 在我看来，这更容易理解——它更清楚地表明你真的不再需要前一个对象中的任何东西了。

你有什么特别的理由想要重用这个对象吗？如果是出于性能原因，您是否测量了性能并发现这是一个瓶颈？我想如果您有一个容量非常大的实例，并且您想避免再次分配它，这可能会很重要……但这对我来说有点像边缘情况。

（所有这些也适用于字典，顺便说一句。我不记得我上次清理字典是什么时候了。）

于 2010-01-04T07:53:57.500 回答
0

我认为与其重用一个扩展的 StringBuilder 对象，不如创建一个新的 StringBuilder 对象。

于 2010-01-04T07:58:15.120 回答