0

我有这个代码

<script>
function cA( url )
{
    document.myform.action = url;
}
</script>

<input type="whatever" name="whatever" id="whatever" />                        
<button class="whatever-button" id="defaultAction" value="Go for it" name="whatever" type="submit" onClick="cA('whatever.php#anchor')" >Go for it                                                                                             
</button>

当您单击 Go for it 按钮时，whatever.php#anchor正在加载。我如何需要更改输入标记的元素才能执行与cA('whatever.php#anchor')单击按钮相同的操作？

因此，当用户在该字段中按下回车键时，whatever.php#anchor应该加载该站点，或者更具体地说，cA('whatever.php#anchor')应该执行该站点。

该页面有更多按钮，因此将一个按钮设为默认按钮不起作用。

PS：

将所有内容包装在一种形式中不起作用，因为页面的结构是

<form>
    <script>
    function cA( url )
    {
        document.myform.action = url;
    }
    </script>

    <input type="whatever1" name="whatever1" id="whatever1" />                        
    <button class="whatever1-button" id="defaultAction1" value="Go for it" name="whatever1" type="submit" onClick="cA('whatever.php#anchor1')" >Go for it                                                                                             
    </button> 

    <input type="whatever2" name="whatever2" id="whatever2" />                        
    <button class="whatever2-button2" id="defaultAction2" value="Go for it" name="whatever2" type="submit" onClick="cA('whatever.php#anchor2')" >Go for it                                                                                             
    </button> 

    <input type="whatever3" name="whatever3" id="whatever3" />                        
    <button class="whatever3-button" id="defaultAction3" value="Go for it" name="whatever3" type="submit" onClick="cA('whatever.php#anchor3')" >Go for it                                                                                             
    </button> 
    ...        
</form>
4

1 回答 1

2

你可以试试这个：

<input type="whatever" name="whatever" id="whatever" onkeydown="if (event.keyCode == 13) {cA('whatever.php#anchor');}" />

查看这篇文章了解更多信息。

于 2013-11-14T11:17:26.193 回答