7

I am trying to update the label in my JavaFx GUI asynchronously with various status message for the application.

For e.g.

A button 'update' in my Application call a method updateSettings() in the controller. Now I am try to update the label on the UI in the following manner.

@FXML
private void updateSettings() {
    label.text("message1");

    //some action

    lable.text("action done");

    label.text("calling method.. wait for some time")
    // call to time consuming method - timeConsumingMethod();

    label.text
    label.text("operation completely successfully");
}

private void timeConsumingMethod() {

    label.text("message2");
    //some actions
    label.text("message3");

    //more  time consuming actions
    label.text("time consuming method is done with success");
}

I want that these messages should be displayed in the label while the flow is getting executed, to show user about the various activities going on in the application.

How to achieve this behavior ?

4

1 回答 1

26

您从 JavaFX 应用程序线程（在Task中）运行耗时的方法。任务中有特殊的 API，可以轻松提供状态消息，这些消息可以显示在绑定标签中。

我对下面的代码所做的是尝试创建一个模仿您在问题中提供的建议流和消息报告的系统。由于代码中记录的各种原因，用户只能看到一些消息。

import javafx.concurrent.Task;
import javafx.scene.Scene;
import javafx.scene.control.*;
import javafx.stage.*;
import javafx.application.*;

public class MessagingDemo extends Application {
  public void start(Stage stage) {
    // "message1" won’t be seen because we perform the next action on the JavaFX 
    // application thread then update the label text again without releasing the 
    // thread to the JavaFX system.
    Label label = new Label("message1");
    label.setPrefWidth(300);

    // some action

    // "action done" won’t be seen because we set text again in the next statement.
    label.setText("action done");

    // you're not going to see this because we immediately bind text to the task text and launch the task. 
    label.text("calling method.. wait for some time") 

    Task <Void> task = new Task<Void>() {
      @Override public Void call() throws InterruptedException {
        // "message2" time consuming method (this message will be seen).
        updateMessage("message2");

        // some actions
        Thread.sleep(3000);

        // "message3" time consuming method (this message will be seen).
        updateMessage("message3"); 

        //more  time consuming actions
        Thread.sleep(7000);

        // this will never be actually be seen because we also set a message 
        // in the task::setOnSucceeded handler.
        updateMessage("time consuming method is done with success");

        return null;
      }
    };

    label.textProperty().bind(task.messageProperty());

    // java 8 construct, replace with java 7 code if using java 7.
    task.setOnSucceeded(e -> {
      label.textProperty().unbind();
      // this message will be seen.
      label.setText("operation completed successfully");
    });

    Thread thread = new Thread(task);
    thread.setDaemon(true);
    thread.start();

    stage.setScene(new Scene(label));
    stage.show();
  }

  public static void main(String args[]) {
    launch(args);
  }
}
于 2013-11-14T04:51:17.217 回答