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给定以下函数依赖关系:ABD -> C和C -> B
这足以说AD -> C吗?
理由是你会得到ABD -> CB,然后B可以从双方移除。
A+ = {A} B+ = {B} C+ = {B,C} D+ = {D} AD+ = {A,D}
你不能从两边删除它们,就像你不能从上面显示的C+中的两边删除 C 一样。所以答案是这两个FD不足以说AD->C