26

我正在遵循给定的示例代码

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
[manager GET:@"http://example.com/resources.json" parameters:nil success:^(AFHTTPRequestOperation *operation, id responseObject) {
    NSLog(@"JSON: %@", responseObject);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"Error: %@", error);
}];

为了更改超时和缓存策略，我“破解”了库并创建了

- (AFHTTPRequestOperation *)GET:(NSString *)URLString
                     parameters:(NSDictionary *)parameters
                          timeoutInterval:(NSTimeInterval)timeoutInterval
                    cachePolicy:(NSURLRequestCachePolicy)cachePolicy
                        success:(void (^)(AFHTTPRequestOperation *operation, id responseObject))success
                        failure:(void (^)(AFHTTPRequestOperation *operation, NSError *error))failure
{
    NSMutableURLRequest *request = [self.requestSerializer requestWithMethod:@"GET" URLString:[[NSURL URLWithString:URLString relativeToURL:self.baseURL] absoluteString] parameters:parameters];
    [request setTimeoutInterval:timeoutInterval];
    [request setCachePolicy:cachePolicy];
    AFHTTPRequestOperation *operation = [self HTTPRequestOperationWithRequest:request success:success failure:failure];
    [self.operationQueue addOperation:operation];

    return operation;
}

有没有一种干净的方法可以做到这一点？

4

5 回答 5

47

我有点懒于分类或子类。您可以直接访问管理器的请求序列化程序：

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
manager.requestSerializer.timeoutInterval = INTERNET_TIMEOUT;
manager.requestSerializer.cachePolicy = NSURLRequestReloadIgnoringLocalAndRemoteCacheData;
于 2014-08-05T10:30:50.083 回答
6

最好是创建一个子类

（也可以同样的方式添加缓存策略）

TimeoutAFHTTPRequestSerializer.h

#import "AFURLRequestSerialization.h"

@interface TimeoutAFHTTPRequestSerializer : AFHTTPRequestSerializer

@property (nonatomic, assign) NSTimeInterval timeout;

- (id)initWithTimeout:(NSTimeInterval)timeout;

@end

TimeoutAFHTTPRequestSerializer.m

#import "TimeoutAFHTTPRequestSerializer.h"

@implementation TimeoutAFHTTPRequestSerializer

- (id)initWithTimeout:(NSTimeInterval)timeout {

    self = [super init];
    if (self) {
        self.timeout = timeout;
    }
    return self;

}

- (NSMutableURLRequest *)requestWithMethod:(NSString *)method
                                 URLString:(NSString *)URLString
                                parameters:(NSDictionary *)parameters
                                     error:(NSError *__autoreleasing *)error
{
    NSMutableURLRequest *request = [super requestWithMethod:method URLString:URLString parameters:parameters error:error];

    if (self.timeout > 0) {
        [request setTimeoutInterval:self.timeout];
    }
    return request;
}

@end

利用

self.requestOperationManager.requestSerializer = [[TimeoutAFHTTPRequestSerializer alloc] initWithTimeout:30];
于 2014-02-01T21:22:38.413 回答
4

您还可以创建一个类别 AFHTTPRequestOperationManager+timeout 来添加此方法，而无需子类化 AFHTTPRequestOperationManager。

于 2014-01-15T17:18:26.807 回答
1

尝试类似：

NSURLRequest *request = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:kRequestTimout];

kRequestTimout你想要的超时时间在哪里

然后构建您的序列化请求：

NSURLRequest *serializedRequest = [self.requestOperationManager.requestSerializer requestBySerializingRequest:request withParameters:parameters error:&error];

并创建并添加您的请求操作：

AFHTTPRequestOperation *operation = [[AFHTTPRequestOperation alloc] initWithRequest:serializedRequest];
[operation setCompletionBlockWithSuccess:successBlock failure:failureBlock];
[self.requestOperationManager.operationQueue addOperation:operation];
于 2014-04-08T10:29:21.507 回答
1

查看方法 1以获得更清洁的方法：https ://stackoverflow.com/a/21238330/435040

不同之处在于我使用的是子类化，而不是修补 AFNetworking 的代码。

有一件事我忘了提。在那个答案中，我只是更改了超时间隔，但添加一些其他缓存策略只是多了 1 行代码。

于 2014-01-20T21:18:48.620 回答